random

How do I generate a random vector in TensorFlow and maintain it for further use?

由 拥有回忆 提交于 2020-01-01 08:44:29
问题 I am trying to generate a random variable and use it twice. However, when I use it the second time, the generator creates a second random variable that is not identical to the first. Here is code to demonstrate: import numpy as np import tensorflow as tf # A random variable rand_var_1 = tf.random_uniform([5],0,10, dtype = tf.int32, seed = 0) rand_var_2 = tf.random_uniform([5],0,10, dtype = tf.int32, seed = 0) #Op1 z1 = tf.add(rand_var_1,rand_var_2) #Op2 z2 = tf.add(rand_var_1,rand_var_2) init

How do I generate a random vector in TensorFlow and maintain it for further use?

由 别说谁变了你拦得住时间么 提交于 2020-01-01 08:44:19
问题 I am trying to generate a random variable and use it twice. However, when I use it the second time, the generator creates a second random variable that is not identical to the first. Here is code to demonstrate: import numpy as np import tensorflow as tf # A random variable rand_var_1 = tf.random_uniform([5],0,10, dtype = tf.int32, seed = 0) rand_var_2 = tf.random_uniform([5],0,10, dtype = tf.int32, seed = 0) #Op1 z1 = tf.add(rand_var_1,rand_var_2) #Op2 z2 = tf.add(rand_var_1,rand_var_2) init

how to fadein LI elements randomly? (jquery)

由 别来无恙 提交于 2020-01-01 07:35:29
问题 Hi I've got a set of <li> with a hover effect, what I want is when the page loads ALL the <li> elements fade-in randomly. I don't want to shuffle them...they should keep their ordering intact meaning 1,2,3,4,5. I just want to make them appear on the page randomly and stay there. Test page: http://humayunrehman.com/hovertest/ 回答1: You can do something like this: var v = $("#blocks > li").css('visibility', 'hidden'), cur = 0; for(var j, x, i = v.length; i; j = parseInt(Math.random() * i), x = v

Behaviour of SecureRandom

由 心已入冬 提交于 2020-01-01 05:10:13
问题 Even though after following many articles on SecureRandom , I encountered a doubt with the usage of SecureRandom Security API in Java. In the below example . public class SecureRandomNumber { public static void main(String[] args) throws NoSuchAlgorithmException { TreeSet<Integer> secure = new TreeSet<Integer>(); TreeSet<Integer> unSecure = new TreeSet<Integer>(); SecureRandom sr = new SecureRandom(); byte[] sbuf = sr.generateSeed(8); ByteBuffer bb = ByteBuffer.wrap(sbuf); long d = bb.getLong

Get a random element in single direction linked list by one time traverse

由 风流意气都作罢 提交于 2020-01-01 04:41:08
问题 I have a single direction linked list without knowing its size. I want to get a random element in this list, and I just have one time chance to traverse the list. (I am not allowed to traverse twice or more) What’s the algorithm for this problem? Thanks! 回答1: This is just reservoir sampling with a reservoir of size 1. Essentially it is really simple Pick the first element regardless (for a list of length 1, the first element is always the sample). For every other element with probability 1/n

How to get random number with negative number in range? [duplicate]

由 牧云@^-^@ 提交于 2020-01-01 03:51:08
问题 This question already has answers here : How do I generate random integers within a specific range in Java? (67 answers) Closed 12 months ago . Consider the following code: int rand = new Random().nextInt((30 - 20) + 1) + 20 It will return a random number between 30 and 20. However, I need its range to include negative numbers. How would I include negative numbers in the generation? I have tried using math that would be negative, but that resulted in an error. Simply subtracting or adding the

random algorithm over all topological sorts of a DAG?

由 混江龙づ霸主 提交于 2020-01-01 03:26:10
问题 Does anyone know of a random algorithm for generating a topological sort of a DAG, where each invocation of the algorithm has a non-zero probability of generating every valid topological sort of the DAG. It's crucial that the algorithm does not preclude any valid topological sort, because it's part of a larger algorithm that, given enough iterations, must be demonstrably capable of exploring all topological sorts of a given DAG. Does anyone know if such an algorithm has been developed?

Scrapy突破反爬虫的限制

由 末鹿安然 提交于 2020-01-01 03:24:00
7-1 爬虫和反爬的对抗过程以及策略 基本概念 爬虫：自动获取网站数据的程序，关键是批量的获取 反爬虫：使用技术手段防止爬虫程序的方法 误伤：反爬技术将普通用户识别为爬虫，如果误伤过高，效果再好也不能用 一般ip地址禁止是不太可能被使用的 成本：反爬虫需要的人力和机器成本 拦截：成功拦截爬虫，一般拦截率越高，误伤率越高 初级爬虫：简单粗暴，不管服务器压力，容易弄挂网站 数据保护： 失控的爬虫：由于某些情况下，忘记或者无法关闭的爬虫 商业竞争对手 爬虫和反爬虫对抗过程 挺有趣的过程 7-2 scrapy架构源码分析 Scrapy Engine: 这是引擎，负责Spiders、ItemPipeline、Downloader、Scheduler中间的通讯，信号、数据传递等等！（像不像人的身体？） Scheduler(调度器): 它负责接受引擎发送过来的requests请求，并按照一定的方式进行整理排列，入队、并等待Scrapy Engine(引擎)来请求时，交给引擎。 Downloader（下载器）：负责下载Scrapy Engine(引擎)发送的所有Requests请求，并将其获取到的Responses交还给Scrapy Engine(引擎)，由引擎交给Spiders来处理， Spiders：它负责处理所有Responses,从中分析提取数据，获取Item字段需要的数据

2.随机森林Random Forest

由 前提是你 提交于 2020-01-01 02:39:43
今天学了菜菜第二章，随机森林。顺便回顾了昨天学的决策树。 具体学到了什么 总结到下面用代码和注释的形式给出，相当于给自己理清楚思路。 划分训练集和测试集的代码： from sklearn.model_selection import train_test_split Xtrain, Xtest, Ytrain, Ytest = train_test_split(wine.data,wine.target,test_size=0.3) # 划分为训练集和测试集的代码 建随机森林的代码（三行）： rfc=RandomForestClassifier(random_state=0) rfc=rfc.fit(Xtrain,Ytrain) score_r=rfc.score(Xtest,Ytest) # 建随机森林来分析的代码 建决策树的代码（三行）： clf=DecisionTreeClassifier(random_state=0) clf=clf.fit(Xtrain,Ytrain) score_c=clf.score(Xtest,Ytest) # 建决策树来分析的代码 交叉验证法（也叫k折交叉验证法）的用法： rfc_l = [] for i in range(10): rfc = RandomForestClassifier(n_estimators=25) rfc_s =

Generate N random numbers in given ranges that sum up to a given sum

由 被刻印的时光 ゝ 提交于 2020-01-01 02:39:42
问题 first time here at Stackoverflow. I hope someone can help me with my search of an algorithm. I need to generate N random numbers in given Ranges that sum up to a given sum! For example: Generatare 3 Numbers that sum up to 11. Ranges: Value between 1 and 3. Value between 5 and 8. value between 3 and 7. The Generated numbers for this examle could be: 2, 5, 4. I already searched alot and couldnt find the solution i need. It is possible to generate like N Numbers of a constant sum unsing modulo
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