python-3.x

问题 I have the following list list1= ['Dodd-Frank', 'insurance', 'regulation'] I used the following to remove the hyphen new1 =[j.replace('-', ' ') for j in list1] The result I got new1= ['Dodd Frank', 'insurance', 'regulation'] The result that Ideally want is new1= ['Dodd', 'Frank', 'insurance', 'regulation'] How can I accomplish this in the most pythonic (efficient way) 回答1: list1 = ['Dodd-Frank', 'insurance', 'regulation'] new1 = '-'.join(list1).split('-') print(new1) Prints: ['Dodd', 'Frank',

问题 I have the following list list1= ['Dodd-Frank', 'insurance', 'regulation'] I used the following to remove the hyphen new1 =[j.replace('-', ' ') for j in list1] The result I got new1= ['Dodd Frank', 'insurance', 'regulation'] The result that Ideally want is new1= ['Dodd', 'Frank', 'insurance', 'regulation'] How can I accomplish this in the most pythonic (efficient way) 回答1: list1 = ['Dodd-Frank', 'insurance', 'regulation'] new1 = '-'.join(list1).split('-') print(new1) Prints: ['Dodd', 'Frank',

问题 I have known for a while that the primary difference between lists and tuples in Python is that lists are mutable and tuples are not. Beyond that and the different methods available to them, I know very little about lists and tuples. Is there any other difference between them? Are there any advantages/disadvantages (aside from immutability) in using a tuple over a list in Python 3? Does one have a faster access time, or have a smaller memory size, or contain more methods, than the other? Are

问题 I have known for a while that the primary difference between lists and tuples in Python is that lists are mutable and tuples are not. Beyond that and the different methods available to them, I know very little about lists and tuples. Is there any other difference between them? Are there any advantages/disadvantages (aside from immutability) in using a tuple over a list in Python 3? Does one have a faster access time, or have a smaller memory size, or contain more methods, than the other? Are

问题 I have the following list list1= ['Dodd-Frank', 'insurance', 'regulation'] I used the following to remove the hyphen new1 =[j.replace('-', ' ') for j in list1] The result I got new1= ['Dodd Frank', 'insurance', 'regulation'] The result that Ideally want is new1= ['Dodd', 'Frank', 'insurance', 'regulation'] How can I accomplish this in the most pythonic (efficient way) 回答1: list1 = ['Dodd-Frank', 'insurance', 'regulation'] new1 = '-'.join(list1).split('-') print(new1) Prints: ['Dodd', 'Frank',

问题 I am going through a link about generators that someone posted. In the beginning he compares the two functions below. On his setup he showed a speed increase of 5% with the generator. I'm running windows XP, python 3.1.1, and cannot seem to duplicate the results. I keep showing the "old way"(logs1) as being slightly faster when tested with the provided logs and up to 1GB of duplicated data. Can someone help me understand whats happening differently? Thanks! def logs1(): wwwlog = open("big

问题 I am going through a link about generators that someone posted. In the beginning he compares the two functions below. On his setup he showed a speed increase of 5% with the generator. I'm running windows XP, python 3.1.1, and cannot seem to duplicate the results. I keep showing the "old way"(logs1) as being slightly faster when tested with the provided logs and up to 1GB of duplicated data. Can someone help me understand whats happening differently? Thanks! def logs1(): wwwlog = open("big

问题 I am going through a link about generators that someone posted. In the beginning he compares the two functions below. On his setup he showed a speed increase of 5% with the generator. I'm running windows XP, python 3.1.1, and cannot seem to duplicate the results. I keep showing the "old way"(logs1) as being slightly faster when tested with the provided logs and up to 1GB of duplicated data. Can someone help me understand whats happening differently? Thanks! def logs1(): wwwlog = open("big

问题 I just set up the VS Code with all the Python extensions. Python version is 3.8.3 through Anaconda. The interpreter is venv. When I run this code import matplotlib.pyplot as plt An error shows - Exception has occurred: AttributeError module 'sip' has no attribute 'setapi' File "C:\test.py", line 145, in <module> import matplotlib.pyplot as plt I've tried uninstalling and reinstalling matplotlib, but to no avail. 回答1: This worked for me. python -m pip install matplotlib==3.2 回答2: There seems

问题 The idea is to be able to build and use the GUI inside the notebook, so working with a long function that has a lot of parameters is more efficient than just typing the characters in the notebook. Obviously not specifics, but if someone can point some library, project, links or any resources that might help. 回答1: I have looked all over internet. So far nothing. There's a message board in PyData where some developer states that jupyter doesn't support GUI. Aside from that, I was thinking