multidimensional-array

How to rightly locate a value at an index in nd array and save it as list in python?

。_饼干妹妹 提交于 2020-03-06 04:20:54
问题 I have a list called L. It has C number of elements. I have a nd array called X. X has Boolean data (either 0 or 1). It has dimension as (20,C). There are 20 lists with each list having C number of elements I want to locate each index that has value of 1 in X.Then I want the value at this same index in List L, and finally store this value from L in another nd array . I write the following code emptylist=[] for index,value in np.ndenumerate(X): #this index is a tuple like (0,3) tuple_to_list

check difference between multidimensional arrays

为君一笑 提交于 2020-03-06 02:16:22
问题 i'm trying a way to remove from a multidimensional array, all the elements equal to another multidimensional array. For example, i've these two arrays; $array1 = Array ( [0] => Array ( [item1] => 3017, [item2] => 7 ), [1] => Array ( [item1] => 3018, [item2] => 4 ), [2] => Array ( [item1] => 3020, [item2] => 9 ), [3] => Array ( [item1] => 3024, [item2] => 5 ) ) and $array2 = Array ( [0] => Array ( [item1] => 3017, [item2] => 7 ), [1] => Array ( [item1] => 3018, [item2] => 200 ), [2] => Array (

Sorting with 2D Arrays

大憨熊 提交于 2020-03-05 10:42:15
问题 I need help with sorting Random numbers into a 2D array. I have to generate 50 random numbers into a column of the array, then sort the numbers in order (ascending or descending). This is what I have so far and am so lost. Please Help. UPDATED VERSION public static void main(String[] args) { int rows = 2; int columns = 50; int[][] anArray = new int[rows][columns]; Random rand = new Random(); for (int i = 0; i < anArray.length; i++) { for (int j = 0; j < anArray[0].length; j++) { int n = rand

Sorting with 2D Arrays

戏子无情 提交于 2020-03-05 10:41:08
问题 I need help with sorting Random numbers into a 2D array. I have to generate 50 random numbers into a column of the array, then sort the numbers in order (ascending or descending). This is what I have so far and am so lost. Please Help. UPDATED VERSION public static void main(String[] args) { int rows = 2; int columns = 50; int[][] anArray = new int[rows][columns]; Random rand = new Random(); for (int i = 0; i < anArray.length; i++) { for (int j = 0; j < anArray[0].length; j++) { int n = rand

Is it possible to usort a multidimensional array in PHP to be ordered by alternative values, i.e 1/0/1/0/1/0

你离开我真会死。 提交于 2020-03-03 07:40:58
问题 If you have this PHP array: $args = array( 'a' => array( 'order' => 1, ), 'b' => array( 'order' => 0, ), 'c' => array( 'order' => 0, ), 'd' => array( 'order' => 0, ), 'e' => array( 'order' => 1, ), ); Is there a way to use usort (or other) method that can order it by multidimensional key's value, but instead of being "incremental" (0,0,0,1,1), they would alternate (0,1,0,1,0). So using the array above as an example, the desired order output is for the keys to be ordered by alternate "order"

How to convert 2Darray into 2D ArrayList in java?

巧了我就是萌 提交于 2020-02-29 07:33:09
问题 I have searched similar questions and I still cannot find the solution for my case. So basically, I have a 2D array called 'array2D' and I am trying to convert those into 2D arrayList. I tried to create an arrayList and used for loop to copy each of the elements from my array2D, which is a primitive 2D Array. I wonder if there is any clean and efficient way to do it. Here is my code: List<List<String>> arrayList2D = new ArrayList<List<String>>(); List<String> eachRecord = new ArrayList<String

How to convert 2Darray into 2D ArrayList in java?

大城市里の小女人 提交于 2020-02-29 07:32:15
问题 I have searched similar questions and I still cannot find the solution for my case. So basically, I have a 2D array called 'array2D' and I am trying to convert those into 2D arrayList. I tried to create an arrayList and used for loop to copy each of the elements from my array2D, which is a primitive 2D Array. I wonder if there is any clean and efficient way to do it. Here is my code: List<List<String>> arrayList2D = new ArrayList<List<String>>(); List<String> eachRecord = new ArrayList<String

Calculate the number of dimensions of a multi-dimensional array in Swift

ⅰ亾dé卋堺 提交于 2020-02-28 07:38:24
问题 Suppose I have some function that I want to populate my data structure using a multi-dimensional array (e.g. a Tensor class): class Tensor { init<A>(array:A) { /* ... */ } } while I could add in a shape parameter, I would prefer to automatically calculate the dimensions from the array itself. If you know apriori the dimensions, it's trivial to read it off: let d1 = array.count let d2 = array[0].count However, it's less clear how to do it for an N-dimensional array. I was thinking there might

Pass N-D array by reference to variadic function

a 夏天 提交于 2020-02-25 06:43:25
问题 I'd like to make the function multi_dimensional accept a multidimensional array by reference. Can this be done with a variation of the syntax below which works for three_dimensional ? #include <utility> // this works, but number of dimensions must be known (not variadic) template <size_t x, size_t y, size_t z> void three_dimensional(int (&nd_array)[x][y][z]) {} // error: parameter packs not expanded with ‘...’ template <size_t... dims> void multi_dimensional(int (&nd_array)[dims]...) {} int

Pass N-D array by reference to variadic function

左心房为你撑大大i 提交于 2020-02-25 06:41:06
问题 I'd like to make the function multi_dimensional accept a multidimensional array by reference. Can this be done with a variation of the syntax below which works for three_dimensional ? #include <utility> // this works, but number of dimensions must be known (not variadic) template <size_t x, size_t y, size_t z> void three_dimensional(int (&nd_array)[x][y][z]) {} // error: parameter packs not expanded with ‘...’ template <size_t... dims> void multi_dimensional(int (&nd_array)[dims]...) {} int