multidimensional-array

问题 I have: $request = Array ( [ID] => 2264 [SUCCESS] => Array ( [0] => Array ( [MESSAGE] => Service Details [LIST] => Array ( [retail_name] => [credit_admin] => FREE [credit] => 0 [discount_admin] => 0 [discount] => 0 [cartdiscount] => 0 If I do: echo $request[ID]; // it says: 2264 echo $request[SUCCESS]; // it says: Array echo $request[SUCCESS][0][MESSAGE]; // it says: Service Details But I need to echo "credit" and if I do: echo $request[SUCCESS][0][LIST]; // I get ERROR echo $request[SUCCESS]

问题 I know how to check if number exist in the array, but not in a 2D array . Please help me in 2D. #include<iostream> using namespace std; int main() { int a[3] = { 4,5,6 }; int b, c; int x = 1, fact = 1; cout << "enter no "; cin >> b; for (int i = 0; i < 3; i++) { if (b == a[i]) { c = a[i]; break; } } cout << "no entered is present" << endl; } 回答1: I know how to check if number exist in the array, but not in 2D array! It is like you did for the one-dimensional array, instead of one, you need to

问题 I have List of Tuple in python as you see below: data = [ (435347,'cat'), (435347,'feline'), (435347,'lion'), (6765756,'dog'), (6765756,'hound'), (6765756,'puppy'), (435347,'kitten'), (987977,'frog') ] how can i convert data into GO equivalent, I have googled it but everywhere they have specified with the same data-type of multidimensional array like this, int_list := [4][2]int{{1, 0}, {2, 0}, {3, 0}, {4, 0}} string_list := make([][]string, 0) a := [1][2]string{{"lion","dog"}} help me out..!

问题 This function shuffles only matrix[y], but I want it to shuffle matrix[y][x] But it doesn't want to shuffle correctly. The code what I used: function Shuffle(arguments) { for (var k = 0; k < arguments.length; k++) { var i = arguments[k].length; if (i == 0) return false; else { while (--i) { var j = Math.floor(Math.random() * (i + 1)); var tempi = arguments[k][i]; var tempj = arguments[k][j]; arguments[k][i] = tempj; arguments[k][j] = tempi; } return arguments; } } return arguments } var

问题 I just had an idea to test something out and it worked: String[][] arr = new String[4][4]; arr[2] = new String[5]; for(int i = 0; i < arr.length; i++) { System.out.println(arr[i].length); } The output obviously is: 4 4 5 4 So my questions are: Is this good or bad style of coding? What could this be good for? And most of all, is there a way to create such a construct in the declaration itself? Also... why is it even possible to do? 回答1: Is this good or bad style of coding? Like anything, it

问题 I have a vector and want to store int data in to it at run time can I store the data in a 2D vector in this manner ? std::vector<std::vector <int>> normal: for(i=0;i<10;i++){ for(j=0;j<20;j++){ normal[i].push_back(j); } } 回答1: Yes, but you also need to push each of the sub-vectors: std::vector<std::vector<int>> normal; for(int i=0; i<10; i++) { normal.push_back(std::vector<int>()); for(int j=0; j<20; j++) { normal[i].push_back(j); } } 回答2: You are manipulating a vector of vectors. As such,

问题 Let's say I have an empty 1D array: var data = []; Now, I want to add value of 1 to data[1][1][3]; To do this, I need to extend data array to: data = [ [], [], [[],[],[1]] ] Yeah, pretty sure that I have to write a function and pass dimension values as 1D array [1, 1, 3] and check 1. if there is second, third dimension and if 'no' create them and 2. if its size are greater or equal. For just this example, function would be function setData(value_, index_){ if(data[index_[0]] == undefined){

问题 I have an array in PHP code below, and I want to convert this array to be grouped by data value. It's always hard to simplify arrays. Original array: Array ( [0] => Array ( [date] => 2017-08-22 [AAA] => 1231 ) [1] => Array ( [date] => 2017-08-21 [AAA] => 1172 ) [2] => Array ( [date] => 2017-08-20 [AAA] => 1125 ) [3] => Array ( [date] => 2017-08-21 [BBB] => 251 ) [4] => Array ( [date] => 2017-08-20 [BBB] => 21773 ) [5] => Array ( [date] => 2017-08-22 [CCC] => 3750 ) [6] => Array ( [date] =>

问题 I am new to Pandas and seeking some advice on a tricky pivot table manipulation please. I have two Pandas pivot tables and a dictionary. The first pivot table has some values that are zero. The second pivot table has the same factors and levels but different values. The dictionary is a set of all possible level pairs for each factor. Sample code: df = pd.DataFrame({'MyColumn1': ['A', 'A', 'B', 'B'], 'MyColumn2': ['M', 'N', 'M', 'P'], 'Value': [1, 1, 1, 1]}) table = pd.pivot_table(df, values=

问题 How can I extract a specific field from each element of a Matlab struct array? >> clear x >> x(1).a = 6; >> x(2).a = 7; I'd like an array containing 6 and 7. Neither x(:).a nor x.a do what I want. >> x(:).a ans = 6 ans = 7 回答1: No problem - just use : arr = [x.a]; It will concat all of the values that you need. If you have a more complex data, you can use the curly bracers: b(1).x = 'John'; b(2).x = 'Doe'; arr = {b.x}; 回答2: For a multi-dimensional array, you need reshape([x.a], size(x)) 回答3: