Educational Codeforces Round 85 (Rated for Div. 2) D. Minimum Euler Cycle(字典序最小的欧拉回路)
【推荐阅读】微服务还能火多久?>>> 目录 传送门 题意: 思路: 代码: 传送门 题意: 思路: 构造的欧拉回路是 1 2 1 3 1 4 1 5……1 n 2 3 2 4 2 5……2 n 3 4 3 5……3 n …… n-1 n 1 一共n*(n-1)+1个数 二分取[L,R]的数即可 代码: # include <iostream> # include <stdio.h> # include <algorithm> # include <string.h> # include <vector> # include <math.h> # include <map> # include <queue> # include <set> # include <stack> # define pb push_back # define lb lower_bound # define ub upper_bound # define fi first # define se second # define all(x) (x).begin(),(x).end() # define SZ(x) ((int)(x).size()) # define debug(x) cout<<x<<endl # define rep(i,a,b) for(int i=a;i<=b;i++) #