loops

how to group array of objects by value in reactjs / javascript

社会主义新天地 提交于 2020-04-10 05:27:13
问题 I have an array of object that have different values like items=[{id:1,category:"cat_1" , title:"My title 1"},{id:2,category:"cat_2" , title:"My title 2"},{id:6,category:"cat_1" , title:"Another title 1"},{id:1,category:"cat_3" , title:"My title 3"},{id:8,category:"cat_1" , title:"Third Title"},{id:2,category:"cat_2" , title:"Another title 2 "}] I use array map to list the object and display them as { items.map((item) => ( <h1>{item.category}</h1> <p>{item.title}</p> ))} My question is how do

Compare 2 arrays and show unmatched elements from array 1 [duplicate]

两盒软妹~` 提交于 2020-04-07 21:13:34
问题 This question already has answers here : How to get the difference between two arrays in JavaScript? (67 answers) Closed 3 years ago . I have 2 arrays as follows. I want to compare both arrays and only provide the elements from 'check' which are not present in 'data' array. var check= ["044", "451"], data = ["343", "333", "044", "123", "444", "555"]; The function used is as follows. This function will result in providing the elements in 'check' array which are present in 'data' array function

Compare 2 arrays and show unmatched elements from array 1 [duplicate]

我的未来我决定 提交于 2020-04-07 21:11:35
问题 This question already has answers here : How to get the difference between two arrays in JavaScript? (67 answers) Closed 3 years ago . I have 2 arrays as follows. I want to compare both arrays and only provide the elements from 'check' which are not present in 'data' array. var check= ["044", "451"], data = ["343", "333", "044", "123", "444", "555"]; The function used is as follows. This function will result in providing the elements in 'check' array which are present in 'data' array function

lapply function /loops on list of lists R

泄露秘密 提交于 2020-04-07 11:00:30
问题 I know this topic appeared on SO a few times, but the examples were often more complicated and I would like to have an answer (or set of possible solutions) to this simple situation. I am still wrapping my head around R and programming in general. So here I want to use lapply function or a simple loop to data list which is a list of three lists of vectors. data1 <- list(rnorm(100),rnorm(100),rnorm(100)) data2 <- list(rnorm(100),rnorm(100),rnorm(100)) data3 <- list(rnorm(100),rnorm(100),rnorm

How to interlace two array lists?

浪子不回头ぞ 提交于 2020-04-07 05:04:12
问题 I am trying to develop a program that shuffles a deck by dividing the deck into two and then interlacing them. Class Deck represents a deck of 52 cards. There are two methods: Deck(int n) and Card drawCard() . Deck(int n) is the constructor. The parameter tells how many rounds the deck should be shuffled. In each round of shuffling, the whole deck is first divided into two sub-decks. The sub-decks are then interlaced into one whole deck. Some notes : To simplify the discussion, we assume the

How to interlace two array lists?

。_饼干妹妹 提交于 2020-04-07 05:04:10
问题 I am trying to develop a program that shuffles a deck by dividing the deck into two and then interlacing them. Class Deck represents a deck of 52 cards. There are two methods: Deck(int n) and Card drawCard() . Deck(int n) is the constructor. The parameter tells how many rounds the deck should be shuffled. In each round of shuffling, the whole deck is first divided into two sub-decks. The sub-decks are then interlaced into one whole deck. Some notes : To simplify the discussion, we assume the

Get unique elements from list of lists when the order of the sublists does not matter

时间秒杀一切 提交于 2020-04-01 02:00:32
问题 I have a list of pairs, representing all edges of cluster in a graph. Actually the list is bigger than this. This is just an example. [[1, 2], [2, 1], [3, 5], [6, 3], [3, 6]] [1, 2] means an edge between nodes 1 and 2, and so does [2, 1] . So, I have some difficulty to eliminate the repeated pairs to count the in-degrees of the cluster. The output should be like [[1, 2], [3, 5], [3, 6]] or [[2, 1], [3, 5], [6, 3]] 回答1: If order of the pairs' elements is irrelevant, then use sorted to

How to check every item inside array?

只谈情不闲聊 提交于 2020-03-25 23:35:47
问题 I have an array of objects and render every item inside it in input and under this section, I have a button that does something I want to check every item "input" if it's empty don't call a function pressed on the button my code works for first object not all, state toolsUsed: [ { id: 0, name: '..', price: '..', count: '..', }, { id: 1, name: '..', price: '..', count: '..', }, ... ], ] here's my iterable array renderToolsUsed = () => { const {toolsUsed} = this.state; return toolsUsed.map((

Update in Batches Never Finishes

£可爱£侵袭症+ 提交于 2020-03-25 21:11:33
问题 as a follow up on my question original question posted here UPDATE in Batches Does Not End and Remaining Data Does Not Get Updated If you use the logic below you'll see that update never finishes. Let me know if you have any ideas why... Table 1 IF OBJECT_ID('tempdb..#Table2') IS NOT NULL BEGIN DROP TABLE #Table2; END CREATE TABLE #Table2 (ID INT); DECLARE @Count int = 0; WHILE (select count(*) from #Table2) < 10000 BEGIN INSERT INTO #Table2 (ID) VALUES (@Count) -- Make sure we have a unique

Calculating the value of pi using a while loop in Python v3

风格不统一 提交于 2020-03-25 16:04:53
问题 This question was migrated from Computer Science Stack Exchange because it can be answered on Stack Overflow. Migrated 25 days ago . I am new to this platform and not sure how to write it as code. And I’ve tried doing this question different ways but my value of pi is 3.414 so I am not sure where I am going wrong. from math import sqrt root = sqrt(2) denominator = sqrt(2 + root) while 2 * (2 / sqrt(2 + denominator) > 1): denominator *= denominator pi = denominator print("Approximation of pi: