location

这篇文章是 社区维基 。 编辑现有答案以改善此职位。 它当前不接受新的答案。 如何使用jQuery或纯JavaScript将用户从一个页面重定向到另一页面？ #1楼 您可以在没有jQuery的情况下做到这一点： window.location = "http://yourdomain.com"; 如果只需要jQuery，则可以这样做： $jq(window).attr("location","http://yourdomain.com"); #2楼 重定向页面的标准“香草” JavaScript方法 window.location.href = 'newPage.html'; 或更简单地说：（因为 window 是“全局”） location.href = 'newPage.html'; 如果您在这里是因为重定向时 丢失了 HTTP_REFERER，请继续阅读： （否则忽略最后一部分） 以下部分适用于那些将 HTTP_REFERER 用作许多安全措施之一的人（尽管这不是很好的保护措施）。 如果您使用的是 Internet Explorer 8 或更低版本，则在使用任何形式的JavaScript页面重定向（location.href等）时，这些变量都会丢失。 下面我们将为 IE8及更低版本 实现替代方案，以免丢失HTTP_REFERER。 否则，您几乎总是可以简单地使用 window

I should use region monitoring in my iOs app for 6 and 7 version. And if my app was closed then system should open it. It works in iOS 6, but not works in iOS 7. I mean, System does not open my app if app was closed in ios 7. About closing app, I mean, kill this app from memory. I use this code: manager = [CLLocationManager new]; manager.delegate = self; [manager startUpdatingLocation]; if ([UIDevice isIOS7OrHigher]) { CLCircularRegion *reg = [[CLCircularRegion alloc] initCircularRegionWithCenter:CLLocationCoordinate2DMake(56.844947, 53.208852) radius:20.f identifier:@"reg14132"]; [manager

调用百度ocr的API，python简易版本 https://www.jianshu.com/p/e10dc43c38d0 1. 注册 百度云注册账号 https://cloud.baidu.com/?from=console 管理应用 https://console.bce.baidu.com/ai/#/ai/ocr/overview/index 创建一个 图1登陆之后的界面 进入链接之后创建应用，由于是从文字识别点进去的，所以默认选中的就是ocr相关内容，填好表格确认。 图2 创建应用之后的界面 有了这三个东西，AppID 、API Key、Secret Key，我们就可以在代码里调用接口了。 2. 调用API 官方指南： https://ai.baidu.com/docs#/OCR-Python-SDK/top 安装使用Python SDK： pip install baidu-aip cv2 需要安装：pip install opencv_python 如果只需要预测文字以及框出文字区域，执行以下代码即可。 import cv2 from aip import AipOcr """ 你的 APPID AK SK 图2的内容""" APP_ID = '14318340' API_KEY = 'DUvK5jEkNmCIEz4cXH8VvIVC' SECRET_KEY = '**

I have in my database car incidents for example. These incidents have a latitude and longitude. On a mobile using the GPS, I get the user's location with his coordinates. The user can select a radius that he wants to know if there are incidents around him. So let's say he want to know incidents 2 miles around him. So I send from the phone to a web service the user's latitude, longitude and the radius he selected. I need to make a SQL query to get the incidents 2 miles around the user. Do you have any idea how to do that? Calculating the distance is pretty computationally expensive, as others

这个字段类型是mysql5.7新增的功能,主要就是解决坐标存储和距离计算的常见问题 创建表: CREATE TABLE `service` ( `id` bigint(20) NOT NULL AUTO_INCREMENT, `name` varchar(128) NOT NULL DEFAULT '', `content` varchar(128) NOT NULL DEFAULT '', `tel` varchar(20) NOT NULL DEFAULT '', `location` geometry NOT NULL, PRIMARY KEY (`id`), KEY `location` (`location`(32)) ) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=utf8 插入坐标 insert into service (name,content,tel,location)values("陶士涵",'牛逼','18898989898',ST_GeomFromText('POINT(116.28828 40.053257)')); 读取坐标 select *,astext(location) from service; 查询距离 SELECT name,content,tel, (st_distance

i dont understand why locationManager.getLastKnownLocation(LocationManager.GPS_PROVIDER); return the location null. I gave all permission but its reutning null . if (isGPSEnabled) { if (location == null) { locationManager.requestLocationUpdates( LocationManager.GPS_PROVIDER, MIN_TIME_BW_UPDATES, MIN_DISTANCE_CHANGE_FOR_UPDATES, this); Log.d("GPS", "GPS Enabled"); if (locationManager != null) { location = locationManager .getLastKnownLocation(LocationManager.GPS_PROVIDER); if (location != null) { latitude = location.getLatitude(); longitude = location.getLongitude(); } } } } I had this exact

Good Day! I am working on an android app which monitors user location. I am using LocationManager to get users location, using the following method public void onLocationChanged(Location theLocation) {} Through the above method, whenever there was a user movement, I am receiving location coordinates. But, now I am planning to get user's location immediately after their app login. Is there any way through LocationManager through which I can manually get the location coordinates after my app launch? Use this technique : LocationManager locManager = (LocationManager)getSystemService(Context

I am trying to utilize GPS in Android (2.2 and 2.3) but am getting the following error when I try to use the LocationManager object: WARN/System.err(522): java.lang.SecurityException: Provider network requires ACCESS_FINE_LOCATION or ACCESS_COARSE_LOCATION permission I have researched the issue in other posts and they are typically due to issues with AndroidManifest.xml. However, mine appears to be fine: <?xml version="1.0" encoding="utf-8"?> <manifest xmlns:android="http://schemas.android.com/apk/res/android" package="com.thedigitalsean.examples" android:versionCode="1" android:versionName="1

Is there any possible way of finding radius of the visible map from the middle point? I want to get the near places against the center point of the map from an API, and that API require lat,lng and radius. I am able to get lat and lng from center point but couldnt find a way to get radius . thanks kaho For the Google Maps Android API, you can get the bounds by... From the map reference, get the Projection by getProjection() . And, a projection is used to translate between on screen location and geographic coordinates.. So from the projection, we can use the getVisibleRegion() , and to get the