load

I'm developing a game using JavaScript and canvas . As the game loads, all images that will be used are being cached. Observing the resource timeline, I see that the following code triggers an asynchronous request: var sprite = new Image(); sprite.src = "sprites/sheet1.png"; The engine will keep executing, eventually beginning to draw and play the level. Images that are loaded after the first frame is painted might never appear due to clipping (i.e. not getting "dirty"). So I tested the following: console.log("begin"); var sprite = new Image(); sprite.onload = function() { console.log('loaded!

Is there an easy way in C# to read a properties file that has each property on a separate line followed by an equals sign and the value, such as the following: ServerName=prod-srv1 Port=8888 CustomProperty=Any value In Java, the Properties class handles this parsing easily: Properties myProperties=new Properties(); FileInputStream fis = new FileInputStream (new File("CustomProps.properties")); myProperties.load(fis); System.out.println(myProperties.getProperty("ServerName")); System.out.println(myProperties.getProperty("CustomProperty")); I can easily load the file in C# and parse each line,

File1.groovy def method() { println "test" } File2.groovy method() I want to load/include the functions/methods from File1.groovy during runtime, equals to rubys/rake's load. They are in two different directories. If you don't mind the code in file2 being in a with block, you can do: new GroovyShell().parse( new File( 'file1.groovy' ) ).with { method() } Another possible method would be to change file1.groovy to: class File1 { def method() { println "test" } } And then in file2.groovy you can use mixin to add the methods from file1 def script = new GroovyScriptEngine( '.' ).with {

Ive been working with CI and I saw on the website of CI you can load a view as a variable part of the data you send to the "main" view, so, according the site (that says a lot of things, and many are not like they say ...ej pagination and others) i did something like this $data['menu'] = $this->load->view('menu'); $this->load->view ('home',data); the result of this is that I get an echo of the menu in the top of the site (before starts my body and all) and where should be its nothing, like if were printed before everything... I have no idea honestly of this problem, did anybody had the same

How can I fire an event when all images in the DOM are loaded? I've googled a lot. I've found this, but it doesn't seem to work: jQuery event for images loaded Use the load() (docs) method against the window . $(window).load(function() { // this will fire after the entire page is loaded, including images }); Or just do it directly via window.onload . window.onload = function() { // this will fire after the entire page is loaded, including images }; If you want a separate event to fire for each image, place a .load() on each image. $(function() { $('img').one('load',function() { // fire when