handler

喜欢尝鲜的同学可能会注意到最新的kubernetes在执行kubectl get cs时输出内容有一些变化，以前是这样的： > kubectl get componentstatuses NAME STATUS MESSAGE ERROR controller-manager Healthy ok scheduler Healthy ok etcd-0 Healthy {"health":"true"} 现在变成了： > kubectl get componentstatuses NAME Age controller-manager <unknown> scheduler <unknown> etcd-0 <unknown> 起初可能会以为集群部署有问题，通过kubectl get cs -o yaml发现status、message等信息都有，只是没有打印出来。原来是kubectl get cs的输出格式有变化，那么为什么会有此变化，我们来一探究竟。 定位问题原因 尝试之前的版本，发现1.15还是正常的，调试代码发现对componentstatuses的打印代码在k8s.io/kubernetes/pkg/printers/internalversion/printers.go中，其中的AddHandlers方法负责把各种资源的打印函数注册进来。 // AddHandlers

喜欢尝鲜的同学可能会注意到最新的kubernetes在执行kubectl get cs时输出内容有一些变化，以前是这样的： > kubectl get componentstatusesNAME STATUS MESSAGE ERRORcontroller-manager Healthy okscheduler Healthy oketcd-0 Healthy {"health":"true"} 现在变成了： > kubectl get componentstatusesNAME Age controller-manager <unknown>scheduler <unknown>etcd-0 <unknown> 起初可能会以为集群部署有问题，通过kubectl get cs -o yaml发现status、message等信息都有，只是没有打印出来。原来是kubectl get cs的输出格式有变化，那么为什么会有此变化，我们来一探究竟。 <!--more--> 定位问题原因 尝试之前的版本，发现1.15还是正常的，调试代码发现对componentstatuses的打印代码在k8s.io/kubernetes/pkg/printers/internalversion/printers.go中，其中的AddHandlers方法负责把各种资源的打印函数注册进来。 //

When trying to learn how to create a delay I researched and found the dominant answer to be to use Handler/Runnable/postDelayed. Handler handler=new Handler(); final Runnable r = new Runnable() { public void run() { delayedMethod(); } }; handler.postDelayed(r, 1000); That worked ok for a while, but I've added a few more things going on and now they are sometimes happening in the wrong order. This set of events: paintScreen1() ... delayedPaintScreen2() ... paintScreen3() is screwing up (sometimes) and doing this: paintScreen1() ... paintScreen3() ... delayedPaintScreen2() (runs last and gets

I'm developing an Android application. This application will have a server to start a DatagramSocket as a server. It will wait for incoming message. When the socket get a message I will process it. To start a UDP Server socket I'm going to use a Local Service. This service will have a worker thread where I'm going to listen to incoming messages. This is my unfinished Local Service implementation: public class UDPSocketBackgroundService extends Service { private static final String TAG = "UDPSocketBackgroundService"; private ThreadGroup myThreads = new ThreadGroup("UDPSocketServiceWorker");

I have converted my custom (socket-based) server over to an HTTP Handler in IIS (.NET 4.0). I have converted my client to send an HTTP GET in the proper format. I do not want to change my client's response-handling code to parse out the HTML code. That is a pain in the rear that is also unnecessary. I do not need this server to work with a browser or be compatible with anything except my client. So, I basically need the HTTP Handler (server) to send the response that the client expects -- without the "HTML/1.0", headers and whatnot. I am using the HttpContext.Response.Write() method at the

I've developed an own implementation of a Chronometer. I did the follow: Create a Service (CronoService), that use a Runnable object that execute the thread. The Runnable will loop each 0.1 secs. Messenger Object that will receive messages from Ui to Start, Pause or Resume the Chronometer. Intent that will broadcast the time after each loop of the Runnable object. The code is: public class CronoService extends Service { public static final int PARAR = 0; public static final int EMPEZAR = 1; public static final int ESTABLECER_TIEMPO = 2; private static final String TAG = "BroadcastService";

1.先看void(*handler)(int),这就是一个函数指针嘛,这步我们可以用typedef来定义函数指针类型 typedef void(*handler)(int),这步简化完后为 typedef void(*handler)(int) void(*signal(int signum, handler h))(int) 2.先把signal(int signum, handler h)扣出来,剩下void(*)(int),又是个函数指针,参数和返回值和上面的一样 然后剩下的signal(int signum, handler h)不就是个函数,说明这个函数的返回值是函数指针类型 3.最终简化为 handler signal(int signum, handler h) 函数名称:signal 参数一:int型 参数二:函数指针型,参数为int,返回值为void 返回值:函数指针型,参数为int,返回值为void 调用实例 #include "stdafx.h" void Fun(int x) { } void(*signal(int signum, void(*handler)(int)))(int) { return Fun; } int _tmain(int argc, _TCHAR* argv[]) { void(*pFun)(int) = signal(1, Fun