google-cloud-firestore

问题 This is my structure of the firestore database: Expected result: to get all the jobs, where in the experience array, the lang value is "Swift". So as per this I should get first 2 documents. 3rd document does not have experience "Swift". Query jobs = db.collection("Jobs").whereArrayContains("experience.lang","Swift"); jobs.get().addOnSuccessListener(new OnSuccessListener<QuerySnapshot>() { @Override public void onSuccess(QuerySnapshot queryDocumentSnapshots) { //Always the

问题 This is my structure of the firestore database: Expected result: to get all the jobs, where in the experience array, the lang value is "Swift". So as per this I should get first 2 documents. 3rd document does not have experience "Swift". Query jobs = db.collection("Jobs").whereArrayContains("experience.lang","Swift"); jobs.get().addOnSuccessListener(new OnSuccessListener<QuerySnapshot>() { @Override public void onSuccess(QuerySnapshot queryDocumentSnapshots) { //Always the

问题 I'm creating a blog Website project using Firebase. What I want is - Create an entirely new Page for the Blog Posts once a USER creates it. FOR EXAMPLE - If a user submits a post with the title: "Best Watches in 2019" . then it should create a new page like: "blog.com/best-watches-in-2019.html" I searched the web a lot about this, but I'm still a beginner in Firebase. Please help me with a solution guys, or a workaround if it's not directly possible. 回答1: The following HTML page shows how you

问题 I'm creating a blog Website project using Firebase. What I want is - Create an entirely new Page for the Blog Posts once a USER creates it. FOR EXAMPLE - If a user submits a post with the title: "Best Watches in 2019" . then it should create a new page like: "blog.com/best-watches-in-2019.html" I searched the web a lot about this, but I'm still a beginner in Firebase. Please help me with a solution guys, or a workaround if it's not directly possible. 回答1: The following HTML page shows how you

问题 I'm creating a blog Website project using Firebase. What I want is - Create an entirely new Page for the Blog Posts once a USER creates it. FOR EXAMPLE - If a user submits a post with the title: "Best Watches in 2019" . then it should create a new page like: "blog.com/best-watches-in-2019.html" I searched the web a lot about this, but I'm still a beginner in Firebase. Please help me with a solution guys, or a workaround if it's not directly possible. 回答1: The following HTML page shows how you

问题 I'm creating a blog Website project using Firebase. What I want is - Create an entirely new Page for the Blog Posts once a USER creates it. FOR EXAMPLE - If a user submits a post with the title: "Best Watches in 2019" . then it should create a new page like: "blog.com/best-watches-in-2019.html" I searched the web a lot about this, but I'm still a beginner in Firebase. Please help me with a solution guys, or a workaround if it's not directly possible. 回答1: The following HTML page shows how you

问题 Would like to know how to filter a Firestore collection of docs using a function where some of the function args are the values of the collection documents. Suppose had some Firestore collection of documents of the form { pointOfInterest: "Some string label" longitude: -100.123 latitude: 50.456 } Also have some code that retrieves a user's geocoordinates (in my case, via react-native), so something like const getCurrentLatLong = () => { // do some stuff, then... return { latitude: someNumber,

问题 I have a function fore firestore in python where I do a for loop for all the users of one collection, then I go into another collection to take some metrics and I update this metrics in the first collections. I run the function but in some point in the execution the function breaks giving me this error: _Rendezvous Traceback (most recent call last) ~\Anaconda3\envs\work\lib\site-packages\google\api_core\grpc_helpers.py in next(self) 78 try: ---> 79 return six.next(self._wrapped) 80 except

问题 I am trying to get readable date from Timestamp data type in my firestore database. for (var ticketDoc of ticketsSnapshot.docs) { var timeStamp = await ticketDoc.data().TimePreferred; console.log(timeStamp.toDate()); var time = new Date(timeStamp).toDate(); ticketDoc.data().TimePreferred = time; tickets.push(ticketDoc.data()); } I read the question about a similar problem at : How do I convert a Firestore date/Timestamp to a JS Date()? so, i tried to do same and i expect the output of

问题 I have an spring-boot application deployed to google cloud using google app engine. There is a datastore with multiple entities. When I try to retrieve data through my app (app is uploaded to appengine, not locally) it always throws an error - There was an unexpected error (type=Internal Server Error, status=500). No API environment is registered for this thread. I am trying to make it work this way: @Bean public FirebaseAuth firebaseAuth() throws IOException { ClassLoader classLoader = this