Javascript Function.prototype.call()
问题 I read some article and it said the following 2 line are doing the same thing. fn.call(thisValue); Function.prototype.call.call(fn, thisValue); For line 1, my understanding is that every function object in Javascript do have a the method call inherited from the Function.prototype and what call method does is to have the this keyword inside the function definition of fn to be thisValue (the first parameter I passed in the call method. fn is a function so what I am doing in fn.call(thisValue)