function

问题 I write down a code which find out quotient after dividing two number but without using multiplication,division or mod operator. My code public int divide(int dividend, int divisor) { int diff=0,count=0; int fun_dividend=dividend; int fun_divisor=divisor; int abs_dividend=abs(dividend); int abs_divisor=abs(divisor); while(abs_dividend>=abs_divisor){ diff=abs_dividend-abs_divisor; abs_dividend=diff; count++; } if(fun_dividend<0 && fun_divisor<0){ return count; } else if(fun_divisor<0||fun

问题 While investigating Emacs Lisp's symbol cells, I found out that for an example function like (defun a (&rest x) x) I can call (symbol-function 'a) , which returns (lambda (&rest x) x) . I can then use it if I want > ((lambda (&rest x) x) 1 2 3 4 5) (1 2 3 4 5) which has the same functionality as the original function above. Now, this reminds me of Scheme where a lambda expression is the body of the function and is assigned to a variable name with Scheme's all-purpose define . For example

问题 I am trying to let a function modify a list by passing the list's reference to it. The program below shows when I pass a list into the function, only a local variable is generated. Is there any ways to select some members from that list within a function? Thank you. def func(list1): list1 = list1[2:] print(list1) # prints [2, 3] list1 = [0, 1, 2, 3] func(list1) print(list1) # prints [0, 1, 2, 3] Edit1: I also tried to use the following function. It also doesn't work. Maybe it's because in

问题 Consider the following functions: def a(): print "a" def b(): print "b" Is there a way to pick a function to run randomly? I tried using: random.choice([a(),b()]) but it returns both functions, I just want it to return one function. 回答1: Only call the selected function, not both of them: random.choice([a,b])() Below is a demonstration: >>> import random >>> def a(): ... print "a" ... >>> def b(): ... print "b" ... >>> random.choice([a,b])() a >>> random.choice([a,b])() b >>> Your old code

问题 Consider the following functions: def a(): print "a" def b(): print "b" Is there a way to pick a function to run randomly? I tried using: random.choice([a(),b()]) but it returns both functions, I just want it to return one function. 回答1: Only call the selected function, not both of them: random.choice([a,b])() Below is a demonstration: >>> import random >>> def a(): ... print "a" ... >>> def b(): ... print "b" ... >>> random.choice([a,b])() a >>> random.choice([a,b])() b >>> Your old code

问题 I'm unable to utilize SQLite window functions (e.g. LAG, LEAD). After some investigation it seems that this is due to the fact that SQLite database version is below 3.25.0, after which window functions were made available. Database created using SQLite 3.30.1 version However version 3.24.0 version displayed on this 'test' database When queries which include window functions are tested, such as the ones provided on sqlitetutorial site: the following errors are displayed Could you please advise

问题 I'm unable to utilize SQLite window functions (e.g. LAG, LEAD). After some investigation it seems that this is due to the fact that SQLite database version is below 3.25.0, after which window functions were made available. Database created using SQLite 3.30.1 version However version 3.24.0 version displayed on this 'test' database When queries which include window functions are tested, such as the ones provided on sqlitetutorial site: the following errors are displayed Could you please advise

问题 I am not sure if this thing has a name, so I couldn't find any information online so far, although surely there is! Imagine my MWE: def PlotElementsDict(dictionary1, dictionary2, itemToPlot, title): # dictionary 1 and dictionary 2 are collections.OrderedDict with 'key':[1,2,3] # i.e. there values of the keys are lists of numbers list1 = [dictionary1[key][itemToPlot] for key in dictionary1.keys()] list2 = [dictoinary2[key][itemToPlot] for key in dictionary2.keys()] plt.plot(list1, label='l1, {

问题 I have an array that has some values inside, and I wish to return another array that has the value grouped in to their own arrays. So the result I am trying to achieve is something like this: var arr = [1,1,2,2,2,3,3,4,4,4,4,5,6] var groupedArr =[[1,1],[2,2,2],[3,3],[4,4,4,4],[5],[6]] 回答1: This proposal works with Array#reduce for sorted arrays. var arr = [1, 1, 2, 2, 2, 3, 3, 4, 4, 4, 4, 5, 6], groupedArr = arr.reduce(function (r, a, i) { if (!i || a !== r[r.length - 1][0]) { return r.concat

问题 I have an array that has some values inside, and I wish to return another array that has the value grouped in to their own arrays. So the result I am trying to achieve is something like this: var arr = [1,1,2,2,2,3,3,4,4,4,4,5,6] var groupedArr =[[1,1],[2,2,2],[3,3],[4,4,4,4],[5],[6]] 回答1: This proposal works with Array#reduce for sorted arrays. var arr = [1, 1, 2, 2, 2, 3, 3, 4, 4, 4, 4, 5, 6], groupedArr = arr.reduce(function (r, a, i) { if (!i || a !== r[r.length - 1][0]) { return r.concat