function

问题 I need some help. Let's say I have the below dataframe called venues_df I also have this function: return_most_common_venues def return_most_common_venues(row, 4): # Selects the row values row_values = row.iloc[1:] # Sorts the selected row values row_values_sorted = row_values.sort_values(ascending=False) # Returns the column name of the first 4 sorted values return row_values_sorted.index.values[0:4] If I apply my function on the first row: return_most_common_venues(venues_df.iloc[0, :], 4)

问题 I'm defining a function for solving my differential equations in scipy's solve_ivp. def conv(t,Z): global sw,von,X if sw==0 and X[1]>=von or sw==1 and X[0]>0: zdot=LA.inv(v1).dot(A1).dot(v1).dot(Z).reshape(4,1)+LA.inv(v1).dot(B1).dot(U) sw=1 von=0.7 X=v1.dot(Z) else: zdot= LA.inv(v0).dot(A0).dot(v0).dot(Z).reshape(4,1)+LA.inv(v0).dot(B0).dot(U) sw=0 X=v0.dot(Z) return np.squeeze(np.asarray(zdot)) and solving my equation using sw=0 e1,v1=LA.eig(A1) von=0 Z= np.array([0, 0, 0, 0]) X=v1.dot(Z) U

问题 So I need to write a program which generates random numbers from 100 to 999, and the tricky part is that the digits in the number can't be the same. For example: 222 , 212 and so on are not allowed. So far, I have this: import random a = int (random.randint(1,9)) <-- first digit b = int (random.randint(0,9)) <-- second digit c = int (random.randint(0,9)) <-- third digit if (a != b and a != b and b != c): print a,b,c As you can see, I generate all three digits separately. I think it's easier

问题 So I need to write a program which generates random numbers from 100 to 999, and the tricky part is that the digits in the number can't be the same. For example: 222 , 212 and so on are not allowed. So far, I have this: import random a = int (random.randint(1,9)) <-- first digit b = int (random.randint(0,9)) <-- second digit c = int (random.randint(0,9)) <-- third digit if (a != b and a != b and b != c): print a,b,c As you can see, I generate all three digits separately. I think it's easier

问题 I can't find it by searching, what is define* in guile? You can find it for instance in this answer https://stackoverflow.com/a/24101699/387194 回答1: You will find it in the documentation here: Creating advanced argument handling procedures. 6.10.4.1 lambda* and define*. lambda* is like lambda, except with some extensions to allow optional and keyword arguments. library syntax: lambda* ([var…] [#:optional vardef…] [#:key vardef… [#:allow-other-keys]] [#:rest var | . var]) body1 body2 …

问题 I can't find it by searching, what is define* in guile? You can find it for instance in this answer https://stackoverflow.com/a/24101699/387194 回答1: You will find it in the documentation here: Creating advanced argument handling procedures. 6.10.4.1 lambda* and define*. lambda* is like lambda, except with some extensions to allow optional and keyword arguments. library syntax: lambda* ([var…] [#:optional vardef…] [#:key vardef… [#:allow-other-keys]] [#:rest var | . var]) body1 body2 …

问题 I have got two arrays of objects. I want to filter data based on permissionObj. This is coming from database. Here are arrays of sub-arrays in the permissionObj. I need to do another condition in reduce function . For example , if Pubsidebar value is token is public, I want to keep static content {label: "test",value: "public"} without filtering with permissionObj and if other key and value is match with permissionObj,then it will be push inside token . let permissionObj = [ { 'OA deal': [ {

问题 I have got two arrays of objects. I want to filter data based on permissionObj. This is coming from database. Here are arrays of sub-arrays in the permissionObj. I need to do another condition in reduce function . For example , if Pubsidebar value is token is public, I want to keep static content {label: "test",value: "public"} without filtering with permissionObj and if other key and value is match with permissionObj,then it will be push inside token . let permissionObj = [ { 'OA deal': [ {

问题 I've created a method, and the return is Result<R> in a class of MyClass<R> , but the error message is 'kotlin.Result' cannot be used as a return type I've also looked into the Result source code for some hints; why is this so? Test code (using v. 1.3-RC). class MyClass<R>(val r:R){ fun f():Result<R>{ // error here return Result.success(r) } } fun main(args: Array<String>) { val s = Result.success(1) val m = MyClass(s) } 回答1: From the Kotlin KEEP: The rationale behind these limitations is

问题 I've created a method, and the return is Result<R> in a class of MyClass<R> , but the error message is 'kotlin.Result' cannot be used as a return type I've also looked into the Result source code for some hints; why is this so? Test code (using v. 1.3-RC). class MyClass<R>(val r:R){ fun f():Result<R>{ // error here return Result.success(r) } } fun main(args: Array<String>) { val s = Result.success(1) val m = MyClass(s) } 回答1: From the Kotlin KEEP: The rationale behind these limitations is