function

问题 I am attempting to create a simple priority based scheduler in XV6. To do this, I also have to create a system call that will allow a process to set its priority. I have done everything required to create the system call as discussed here and elsewhere: how do i add a system call / utility in xv6 The problem is, I cannot pass any variables when I call the function, or rather, it runs like nothing is wrong but the correct values do not show up inside the function. Extern declaration (syscall.c

问题 I need to return a median of only a certain category on a spread sheet. Example Below Airline 5 Auto 20 Auto 3 Bike 12 Airline 12 Airline 39 ect. How can I write a formula to only return a median value of the Airline Categories. Similar to Average if, only for median. I cannot re-arrange the values. Thank you! 回答1: Assuming your categories are in cells A1:A6 and the corresponding values are in B1:B6, you might try typing the formula =MEDIAN(IF($A$1:$A$6="Airline",$B$1:$B$6,"")) in another

问题 I want to use an object as function argument. When I define an object outside fucntion and then pass it as an argument, it works fine: var obj = { a: 0 } function foo(obj){ console.log(this.obj.a); } foo() //0 But when I pass an object directly, it doesen't work: function bar({a: 0}){ console.log(this.arguments.a) } // Uncaught SyntaxError: Unexpected number An object doesent seem to be a legal argument. How do I fix it? 回答1: ES6 supports parameters destructuring. You can use: function bar({a

问题 I want to use an object as function argument. When I define an object outside fucntion and then pass it as an argument, it works fine: var obj = { a: 0 } function foo(obj){ console.log(this.obj.a); } foo() //0 But when I pass an object directly, it doesen't work: function bar({a: 0}){ console.log(this.arguments.a) } // Uncaught SyntaxError: Unexpected number An object doesent seem to be a legal argument. How do I fix it? 回答1: ES6 supports parameters destructuring. You can use: function bar({a

问题 Are calling method and called method both same? What I would like to know is "calling method" means the method which calls another method that is main method in most cases, or the main method itself? 回答1: The calling method is the method that contains the actual call; the called method is the method being called. They are different. For example: // Calling method void f() { g(); } // Called method void g() { } 回答2: The calling method is the method that contains the actual call. The called

问题 Are calling method and called method both same? What I would like to know is "calling method" means the method which calls another method that is main method in most cases, or the main method itself? 回答1: The calling method is the method that contains the actual call; the called method is the method being called. They are different. For example: // Calling method void f() { g(); } // Called method void g() { } 回答2: The calling method is the method that contains the actual call. The called

问题 This is the working code: var test = function () { console.log(test.data); }; test.data = 'hello'; test.set = function (data) { test.data = data; }; test.set('Test'); test(); This outputs Test to my javascript console. Now I was wondering, if there was a way to do it using something like this? var test = { this: function () { console.log(test.data); }, data: 'hello', set: function (data) { test.data = data; } }; 回答1: As I have written in my comment, you cannot make an object "callable". You

问题 This is the working code: var test = function () { console.log(test.data); }; test.data = 'hello'; test.set = function (data) { test.data = data; }; test.set('Test'); test(); This outputs Test to my javascript console. Now I was wondering, if there was a way to do it using something like this? var test = { this: function () { console.log(test.data); }, data: 'hello', set: function (data) { test.data = data; } }; 回答1: As I have written in my comment, you cannot make an object "callable". You

问题 Given a function in C++ with arguments that are only types and have no identifiers, void foo1(int, int, int){cout << "called foo1";} I can call it as such: int main() { foo1(10, 10, 10); } Why is this a valid construct in C++? Is this just an idiosyncrasy of C++, or does this kind of declaration actually have some purpose? Can we actually access the arguments that have been passed in somehow? (This kind of method declaration will not work in Java.) 回答1: Consider a case where you are required

问题 Given a function in C++ with arguments that are only types and have no identifiers, void foo1(int, int, int){cout << "called foo1";} I can call it as such: int main() { foo1(10, 10, 10); } Why is this a valid construct in C++? Is this just an idiosyncrasy of C++, or does this kind of declaration actually have some purpose? Can we actually access the arguments that have been passed in somehow? (This kind of method declaration will not work in Java.) 回答1: Consider a case where you are required