function

问题 I want to mimic this behaviour of Python3.8 in Python3.7 Positional-only parameters / was the syntax introduced to indicate that some function parameters must be specified positionally and cannot be used as keyword arguments. #Python3.8 def f(a,b,/,**kwargs): print(a,b,kwargs) >>> f(1,2,**{'a':100,'b':200,'c':300}) # 1 2 {'a': 100, 'b': 200, 'c': 300} a , b are used only as positional parameters. How I do the same in Python3.7 #Python3.7 def f(a,b,**kwargs): print(a,b,kwargs) >>> f(1,2,**{'a'

问题 This question already has answers here : Javascript call() & apply() vs bind()? (20 answers) Closed 7 years ago . var obj = { x: 81, getX: function() { console.log( this.x) } }; var getX = obj.getX.bind(obj);//use obj as 'this'; getX();//81 var getX = function(){ obj.getX.apply(obj); } getX();//also 81 The use of bind and call/apply look very similar, I want to know what's the difference between them.The two getX Function above is the same? 回答1: bind returns a function which will act like the

问题 This question already has answers here : Javascript call() & apply() vs bind()? (20 answers) Closed 7 years ago . var obj = { x: 81, getX: function() { console.log( this.x) } }; var getX = obj.getX.bind(obj);//use obj as 'this'; getX();//81 var getX = function(){ obj.getX.apply(obj); } getX();//also 81 The use of bind and call/apply look very similar, I want to know what's the difference between them.The two getX Function above is the same? 回答1: bind returns a function which will act like the

问题 I am a student studying an online course in computer programming. So far, I seem to be doing well throughout the Spring semester. However, I was assigned homework this week that is designed to test my knowledge of Java functions. I am supposed to write a program that asks a user to enter 4 integers, then determines whether those 4 entries form a square or a rectangle. If the 4 entries do make a square or rectangle, then the supposed program has to calculate its perimeter. The output is

问题 Question: What are the basic rules and boundaries (in terms of syntax) that need to be considered when writing any closure in swift? 回答1: Closure Rules: If the closure block solely returns value after the 'in' keyword (or the closure block just returns a value) then using 'return' keyword is optional. Defining closure argument type is optional if the closure type is explicitly defined. Defining closure return type is optional, if closure arguments are defined with it's type and there is no

问题 Question: What are the basic rules and boundaries (in terms of syntax) that need to be considered when writing any closure in swift? 回答1: Closure Rules: If the closure block solely returns value after the 'in' keyword (or the closure block just returns a value) then using 'return' keyword is optional. Defining closure argument type is optional if the closure type is explicitly defined. Defining closure return type is optional, if closure arguments are defined with it's type and there is no

问题 Closed . This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 19 days ago . I need your help or if you can give me advice. I'm really struggling and some help would be perfect, so this is what I got so far; import BST, TreeNode class Bibliography: def __init__(self): self.bibtree = BST() def getReference(self,key): """Return the reference for the key, if it exists,

问题 This question already has answers here : Call function without parameter and parenthesis (3 answers) Closed 9 days ago . When run, I cannot input anything and the program just end and return nothing, though in my code I want to input and output something. And then I tried to debug, I set a lot of key points in the function that I defined, but it directly goes to the end of the code. It seems that the function I defined can't be run. I am confused about that. Could you tell me what was wrong?

问题 I am learning C++ and I can never tell when I need to use :: . I do know that I need to use std:: in front of cout and cin . Does this mean that inside of the iostream file the developers that created it made a namespace called std and put the functions cin and cout into the namespace called std ? When I created a new class that isn't in the same file as main() for some reason I must add :: . For example, if I create a class called A , why do I need to put A:: in front of a function that I

问题 I am learning C++ and I can never tell when I need to use :: . I do know that I need to use std:: in front of cout and cin . Does this mean that inside of the iostream file the developers that created it made a namespace called std and put the functions cin and cout into the namespace called std ? When I created a new class that isn't in the same file as main() for some reason I must add :: . For example, if I create a class called A , why do I need to put A:: in front of a function that I