forms

Create a form container with Angular JS component

由 大兔子大兔子 提交于 2020-01-06 15:12:58
问题 I am using Angular JS 1.5.6 and I would like to use only component and not directive. I have more than 5 views using a form in my application. The style of the form is exactly the same in all the views, it is only the content of the form that changes. I have made components (input, button, etc..) and I would like to create a component for the form, it would be like a container component, in which I can put different components. In view A, the form will contain 1 button and 1 input, in view B

Create a form container with Angular JS component

由 為{幸葍}努か 提交于 2020-01-06 15:09:30
问题 I am using Angular JS 1.5.6 and I would like to use only component and not directive. I have more than 5 views using a form in my application. The style of the form is exactly the same in all the views, it is only the content of the form that changes. I have made components (input, button, etc..) and I would like to create a component for the form, it would be like a container component, in which I can put different components. In view A, the form will contain 1 button and 1 input, in view B

Code Igniter URL appending

由 左心房为你撑大大i 提交于 2020-01-06 15:04:33
问题 This is my first question, I am new at CodeIgniter and trying to run a login code at XAMPP server. I have two views. myform.php <html> <head> <title>My Form</title> </head> <body> <?php echo validation_errors(); ?> <form id="myform" method="post" action="/form/myform" title="Create an Account"> <h5>Username</h5> <input type="text" name="username" value="<?php echo set_value('username'); ?>" size="50" /> <h5>Password</h5> <input type="text" name="password" value="<?php echo set_value('username

Submit form, then send form data to ajax from a new page

由 [亡魂溺海] 提交于 2020-01-06 14:54:28
问题 I have a form on page1.php which redirects to page2.php, I want to pass the data from the form to page3.php immediately on load of page2.php. (the user doesn't need to see what's going on in page3, only page2) What should I use to pass the variables? Currently I'm using page1.php <html> <form action=page2.php method=post> <!-- form content here incl name attr for input elements --> </form> </html> page2.php <body> <?php $var1 = $_POST['name1']; // int $var2 = $_POST['name2']; // int $var3 = $

How to hide the default value of a form field?

由 只谈情不闲聊 提交于 2020-01-06 14:53:15
问题 I have a form with two options - 10 and Other - and then a text field next to Other so you can enter a desired amount. Here's the way I have it set up now: <input class="mainForm" id="Amount" name="Amount" type="radio" value="10"> <label class="formFieldOption">10</label> <input class="mainForm" id="Amount" name="Amount" type="radio" value="other"> <label class="formFieldOption">Other: $ <input class="mainForm" id="Amount" name="Amount" size="10" type="text" value="10"> </label> With this

AjaxForms: Some working some not

由 耗尽温柔 提交于 2020-01-06 14:09:45
问题 This is how my view looks like currently. @model DatePicker.Models.ViewModels.Appointment.CreateAppointmentSelectPersons @{ ViewBag.Title = "Create"; Layout = "~/Views/Shared/_Layout.cshtml"; <link href="~/Content/themes/base/minified/jquery-ui.min.css" rel="stylesheet"/> } @*Main Form*@ @using(Ajax.BeginForm("Create","Appointment", new AjaxOptions{HttpMethod = "POST"})) { @Html.AntiForgeryToken() <h4>Step 2</h4> <hr /> @Html.ValidationSummary() @Html.HiddenFor(m=>m.AppointmentId) @*Child

AjaxForms: Some working some not

由 百般思念 提交于 2020-01-06 14:08:40
问题 This is how my view looks like currently. @model DatePicker.Models.ViewModels.Appointment.CreateAppointmentSelectPersons @{ ViewBag.Title = "Create"; Layout = "~/Views/Shared/_Layout.cshtml"; <link href="~/Content/themes/base/minified/jquery-ui.min.css" rel="stylesheet"/> } @*Main Form*@ @using(Ajax.BeginForm("Create","Appointment", new AjaxOptions{HttpMethod = "POST"})) { @Html.AntiForgeryToken() <h4>Step 2</h4> <hr /> @Html.ValidationSummary() @Html.HiddenFor(m=>m.AppointmentId) @*Child

Successful Ajax post displays error message

由 荒凉一梦 提交于 2020-01-06 14:07:50
问题 My form properly submits data via POST utilizing Ajax. However I am trying to redirect the user upon successful submission. The problem is, even though the form successfully submits, instead of redirecting the user it displays an error. According to firebug the page I am submitting to, is throwing up a 200 success code. I am using jquery 1.8.3. My Code: $(document).ready(function() { $("#form4").submit(function(e) { e.preventDefault(); var frm = $('#form4'); $.ajax({ type: 'POST', url: 'http:

Best way to code PHP/MYSQL search with options [closed]

由 这一生的挚爱 提交于 2020-01-06 14:04:34
问题 Closed . This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 4 years ago . So I am building a search form which has a lot of options for users to select from. As you can see from the image below a user selects a search criteria and it allows them to enter or check what they like. If this is unticked it removes all values/unchecks all the boxes. I

Best way to code PHP/MYSQL search with options [closed]

由 心不动则不痛 提交于 2020-01-06 14:03:53
问题 Closed . This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 4 years ago . So I am building a search form which has a lot of options for users to select from. As you can see from the image below a user selects a search criteria and it allows them to enter or check what they like. If this is unticked it removes all values/unchecks all the boxes. I
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