forms

Generating form with hidden input and submitting to an action

点点圈 提交于 2020-01-07 01:21:50
问题 I thought this would be a lot simpler than it had been. I need to extract data from a cell in my datatable (Which I can do) and then submit it via a form with a hidden field in order to pass the variable to an action in my controller. I am doing something similar to this prior in my code with the exception of generating the form. I have tried different methods and not matter what when I access the collection in my action the value is null. My View function: $('#myTable').on('click', 'td',

PHP - Automatically Submitting/Running A Form

 ̄綄美尐妖づ 提交于 2020-01-07 01:21:24
问题 I recently posted a question about php forms with a checkbox that simply echoed the result and it was answered. However i now have the question how can i automatically submit the form so rather than waiting for the submit button to be clicked once it would automatically echo the result. I would like a way to run the form once because i wanted to make far more complex forms and would like to display the initial result right away. The other thread: PHP - Form Elements Resetting Many thanks 来源:

How to disable button if textbox is empty

我怕爱的太早我们不能终老 提交于 2020-01-07 00:36:37
问题 First of all sorry for my bad english. I'm beginner at C# and i made a Windows forms application but i can't disable one button if a textbox is empty. I tried some of the Enabled methods but they didn't work. Hope someone can help me fix this. Thank you very much public partial class ModulusForm : Form { public double nje; public double dy; public double pergjigja; public double rezultati; public ModulusForm() { InitializeComponent(); Button btn = new Button(); btn.Click += new EventHandler

html form name= php variable

亡梦爱人 提交于 2020-01-07 00:36:02
问题 I have a form (basically a test) that the users has to fill in. The question nr I get from the MySQL table but I can not get the question number carried over to the answer.php file. form $sql1="SELECT * FROM ex_question WHERE test_name = '$tid' ORDER BY RAND() LIMIT 5"; $result1=mysql_query($sql1); while($row1 = mysql_fetch_array($result1)) { $test_name=$row1['test_name']; $q_nr=$row1['q_nr']; $q_type=$row1['q_type']; $question=$row1['question']; $option1=$row1['option1']; $option2=$row1[

How to upload File to server from android?

不羁岁月 提交于 2020-01-07 00:07:38
问题 I have a problem with uploading file to the server. Here i'm trying to create the registration form. I need to upload all values that taken from user, along with that i need to upload the resume resume is in PDF format. Here is my code. Please look into it. ...... ...... //here is the connection part URL url = new URL(mUrl); connection = (HttpURLConnection) url.openConnection(); connection.setDoInput(true); connection.setDoOutput(true); connection.setUseCaches(false); // Don't use a Cached

How do I completely overwrite previously edited data such that only the latest one is displayed in Codeigniter?

a 夏天 提交于 2020-01-06 23:44:20
问题 I have checked all other related posts but 'could not find any that answers my specific question. Here's what I have: <input name="job_id" type="hidden" value="<?= $this->uri->segment(3, 0); ?>" /> <?php foreach ($my_preference as $row) : if ( $row['status'] == "Open" ) { $bgcolor = "#ADD8E6"; } else if ( $row['status'] == "Approved" ) { $bgcolor = "#8CBEE8"; } else { $bgcolor = "#EDC2B6"; } ?> <span style="font-size: 11pt" class="label label-info"> Proposal</span>     <strong><?= $row[

Keep checked radio button checked through forms C# Visual Studio 2010

懵懂的女人 提交于 2020-01-06 22:47:44
问题 I have a form with 10 radio buttons (Form2)for a user to check (all in same group). Then a button to go to the next form (Form3). On Form3 I have a back button to go back to Form2 to change the radio button if needed. When the back button is pressed, it goes to Form2 with all of the radio buttons, but it doesn't show the previously checked radio button. Example code: string SchoolName = ""; if (radioButton1.Checked) { SchoolName = radioButton1.Text; } if (radioButton2.Checked) { SchoolName =

Keep checked radio button checked through forms C# Visual Studio 2010

泄露秘密 提交于 2020-01-06 22:47:22
问题 I have a form with 10 radio buttons (Form2)for a user to check (all in same group). Then a button to go to the next form (Form3). On Form3 I have a back button to go back to Form2 to change the radio button if needed. When the back button is pressed, it goes to Form2 with all of the radio buttons, but it doesn't show the previously checked radio button. Example code: string SchoolName = ""; if (radioButton1.Checked) { SchoolName = radioButton1.Text; } if (radioButton2.Checked) { SchoolName =

Access Form cant update or add records

杀马特。学长 韩版系。学妹 提交于 2020-01-06 21:58:33
问题 I am currently creating a Form on access however when I go into form view I am unable to update any of the current records or add new records would anyone have any idea why I cant edit or update my records? or how I go about fixing this? My Form is currently linked to a query, and incase it matters I also have inlcuded a search function in my form. Any help/advice would be greatly appreciated. Thanks Paula 回答1: It means that the query you use is not updateable. There are a lot of limitations

Read php file using php file and excel export

女生的网名这么多〃 提交于 2020-01-06 21:52:52
问题 I have two files like below. What I'm trying to do is, I want to fetch the second file content in first file, and then export it to xls. What is the problem with the below code. My intension is to - read a second php file using first php file, and then excel export that content into .xls in C:/myfiles/test.xls index.php <?php $read_file = readfile("my_export_file.php"); $file = 'test.xls'; header("Content-type: application/vnd.ms-excel"); header("Content-Disposition: attachment; filename=