format

问题 I am new to Python. I am trying to adjust the format of a list which looks like below: data=[1,10,313,4000,51234,123456] and I would like to convert them to a list of strings with leading zeros: result=['000001','000010','000313','004000','051234','123456'] each of the element has 6 digits. I know for a single number X, I can do: str(X).zfill(6) but I am not sure how to apply this to a list. I would like to solve this problem without using a for loop. Anyone could help? Thanks. 回答1: Apply the

问题 I am new to Python. I am trying to adjust the format of a list which looks like below: data=[1,10,313,4000,51234,123456] and I would like to convert them to a list of strings with leading zeros: result=['000001','000010','000313','004000','051234','123456'] each of the element has 6 digits. I know for a single number X, I can do: str(X).zfill(6) but I am not sure how to apply this to a list. I would like to solve this problem without using a for loop. Anyone could help? Thanks. 回答1: Apply the

来源： https://stackoverflow.com/questions/43247785/can-i-print-object-as-string-like-date-in-console-log

来源： https://stackoverflow.com/questions/43247785/can-i-print-object-as-string-like-date-in-console-log

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来源： https://stackoverflow.com/questions/49247661/how-to-add-comma-thousand-separator-in-power-bi-query-editor

来源： https://stackoverflow.com/questions/49247661/how-to-add-comma-thousand-separator-in-power-bi-query-editor

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来源： https://stackoverflow.com/questions/55513198/is-there-a-more-concise-way-to-format-expect-message

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