firebug

问题 Firebug is certainly a wonderful tool for javascript debugging; I use console.log() extensively. I wanted to know if I can leave the Firebug-specific code in production. What's the best practice? Commenting the debug code? 回答1: If you leave console.log() calls in your production code, then people visiting the site using Internet Explorer will have JavaScript errors. If those people have extra debugging tools configured, then they will see nasty dialog boxes or popups. A quick search revealed

问题 var list = []; $.getJSON("json.js", function(data) { $.each(data, function(i, item) { console.log(item.text); list.push(item.text); }); }); console.log(list.length); list.length always returns 0. I've browsed the JSON in firebug and it's well formed and everything looks fine. I just can't seem to add an item to the array what am I missing? 回答1: Since $.getJSON is async, I think your console.log(list.length); code is firing before your array has been populated. To correct this put your console

问题 style.css - Original File .box { -webkit-border-radius:8px; -moz-border-radius:8px; padding:10px; } style.css - In Firebug CSS Console .box { -moz-border-radius:8px 8px 8px 8px; padding:10px; } How can I force Firebug to show my -webkit css styles as well? Thanks for your help! 回答1: I don't think you can - the correct behaviour for browsers is to ignore style rules they don't understand. Firefox sees -webkit-xxx and effectively removes it from the style set, so it can't ever be applied to

问题 How can I view the page headers sent by the current page I'm viewing in Firebug ? 回答1: Yes, so long as Firebug is open on the net or console tabs when loading the page. They will appear in either one of these tabs (though you may need to reload if they were not enabled/open). 来源： https://stackoverflow.com/questions/4156079/viewing-page-headers-in-firebug

问题 How can I view the page headers sent by the current page I'm viewing in Firebug ? 回答1: Yes, so long as Firebug is open on the net or console tabs when loading the page. They will appear in either one of these tabs (though you may need to reload if they were not enabled/open). 来源： https://stackoverflow.com/questions/4156079/viewing-page-headers-in-firebug

问题 Creating a table without tbody using javascript createElement/appendChild will not add tbody in Firebug but using innerHTML will do it. Why? Should we add the tbody manually? 回答1: When using DOM creation methods, it must assume that you want the structure the way you created it. If you want to ensure the same structure in different browsers, then yes you should always add it manually, even when JavaScript is parsing the HTML. Don't rely on the browser to insert it for you, because browsers

问题 Look: ! Wow! How can the webpage know I'm using firebug? BTW I couldn't find out how to show the translucent add banner. 回答1: You can do: if(window.console && window.console.firebug) { alert("Firebug active!"); } 回答2: This works not only from the Firebug console, but also from within the page: if (document.getElementById('_firebugConsole')) alert("fire!"); 回答3: Both answers will alert if the Firebug user has activated the Console panel. If users disable the Console panel, but leave the rest

问题 Google Developer Tools "Network" Tab clears after redirect to another page and i want to know if there is any way to keep all request? I want to do this because i want to verify one POST request but it redirects and get cleared. In firebug we can use the "Persist" option: (The "Persist" option prevents clearing the console at a page reload. That means, the messages will stay inside the console as long as this option is enabled.) https://getfirebug.com/wiki/index.php/Console_Panel 回答1: In the

问题 I am using Firefox and Firebug's command line to execute a JavaScript on two different sites: https://graph.facebook.com/v2.3/172727819415642/albums?fields=id,name,cover_photo,photos%7Bname,source%7D&limit=1&access_token=xxxxx http://www.iskcondesiretree.com/photo/album/list Here's the code: (function() { function r() { a = $("body").text() console.log(a); }; var e = "1.6.4"; var t = false; if (!t) { t = true; var n = document.createElement("script"); n.src = "https://ajax.googleapis.com/ajax

问题 I just got this error message in Firebug. A google search reveals nothing but other mystified people! Does anyone have any idea what it means? It's being indicated on the last line of this 3-line script: <script> g_BuildServer = "/"; </script> 回答1: If you put JavaScript in a js file (which I assume you did), do NOT put the script tags, put g_BuildServer = "/"; only. Otherwise, to the parser, you just provided an XML document as a script. 回答2: I got this error when using jquery $get with no