executable-jar

问题 Execution default of goal org.springframework.boot:spring-boot-maven-plugin:1.0.1.RELEASE:repackage failed: Unable to find a single main class from the following candidates My project has more than one class with a main method. How do I tell the Spring Boot Maven plugin which of the classes it should use as the main class? 回答1: Add your start class in your pom: <properties> <!-- The main class to start by executing java -jar --> <start-class>com.mycorp.starter.HelloWorldApplication</start

问题 This question already has an answer here: Java Jar file: use resource errors: URI is not hierarchical 6 answers I have files in resource folder. For example if I need to get file from resource folder, I do like that: File myFile= new File(MyClass.class.getResource(/myFile.jpg).toURI()); System.out.println(MyClass.class.getResource(/myFile.jpg).getPath()); I\'ve tested and everything works ! The path is /D:/java/projects/.../classes/X/Y/Z/myFile.jpg But , If I create jar file, using , Maven :

问题 I\'m trying to pass String as parameter from one Java Aplications to second as StartUp parameter for example I have Aplications that must call start another Java Aplication (just contains only JOptionPane, JDialog or simple JFrame) before System.exit(0); , there I trying to send some descriptions from closing application to another, these code is simulations what I tried that and in this form, code works correctly and displayed String into the JTextArea ... import java.io.IOException; import

问题 How could I run a local jar file from a java program? The jar file is not in the class-path of the Java caller program. 回答1: I suggest you use a ProcessBuilder and start a new JVM. Here is something to get you started: ProcessBuilder pb = new ProcessBuilder("/path/to/java", "-jar", "your.jar"); pb.directory(new File("preferred/working/directory")); Process p = pb.start(); 回答2: Process proc = Runtime.getRuntime().exec("java -jar Validate.jar"); proc.waitFor(); // Then retreive the process

问题 I am trying to generate an executable jar for a small home project called \"logmanager\" using maven, just like this: How can I create an executable JAR with dependencies using Maven? I added the snippet shown there to the pom.xml, and ran mvn assembly:assembly. It generates two jar files in logmanager/target: logmanager-0.1.0.jar, and logmanager-0.1.0-jar-with-dependencies.jar. I get an error when I double-click on the first jar: Could not find the main class: com.gorkwobble.logmanager

问题 I have deployed my app to jar file. When I need to copy data from one file of resource to outside of jar file, I do this code: URL resourceUrl = getClass().getResource(\"/resource/data.sav\"); File src = new File(resourceUrl.toURI()); //ERROR HERE File dst = new File(CurrentPath()+\"data.sav\"); //CurrentPath: path of jar file don\'t include jar file name FileInputStream in = new FileInputStream(src); FileOutputStream out = new FileOutputStream(dst); // some excute code here The error I have

问题 My java program is packaged in a jar file and makes use of an external jar library, bouncy castle. My code compiles fine, but running the jar leads to the following error: Exception in thread \"main\" java.lang.SecurityException: Invalid signature file digest for Manifest main attributes I\'ve googled for over an hour searching for an explanation and found very little of value. If anyone has seen this error before and could offer some help, I would be obliged. 回答1: The solution listed here

问题 I had written several simple java applications named as A.jar, B.jar. Now i want to write a GUI java program so that user can press button A to execute A.jar and button B to execute B.jar. Also i want to output the run-time process detail in my GUI program. Any suggestion? 回答1: If I understand correctly it appears you want to run the jars in a separate process from inside your java GUI application. To do this you can use: // Run a java app in a separate system process Process proc = Runtime

问题 Want to improve this post? Provide detailed answers to this question, including citations and an explanation of why your answer is correct. Answers without enough detail may be edited or deleted. My code runs inside a JAR file, say foo.jar, and I need to know, in the code, in which folder the running foo.jar is. So, if foo.jar is in C:\\FOO\\ , I want to get that path no matter what my current working directory is. 回答1: return new File(MyClass.class.getProtectionDomain().getCodeSource()

问题 I have a JAR file named helloworld.jar . In order to run it, I\'m executing the following command in a command-line window: java -jar helloworld.jar This works fine, but how do I execute it with double-click instead? Do I need to install any software? 回答1: Easiest route is probably upgrading or re-installing the Java Runtime Environment (JRE). Or this: Open the Windows Explorer, from the Tools select 'Folder Options...' Click the File Types tab, scroll down and select JAR File type. Press the