电话

delphi XE5开发Android程序调用电话相关功能(短信息和电话)

五迷三道 提交于 2019-12-05 08:27:47
XE5开发Android程序调用电话相关功能(短信息和电话) 时间:2013-9-19 16:46:08 点击:5570   核心提示: 其实都可以通过intent和URI调用系统功能.Windows程序员可以理解成是ShellExecute.这个是万金油.可以有调用各种功能.后面会介绍.1.短信息.很简单方法a.不使用Intent而是直接发短信.smsManager对应的Delphi代码应该是:uses Androidapi.JNI... 其实都可以通过intent和URI调用系统功能.Windows程序员可以理解成是ShellExecute.这个是万金油.可以有调用各种功能.后面会介绍. 1.短信息.很简单 方法a.不使用Intent而是直接发短信. smsManager对应的Delphi代码应该是: uses Androidapi.JNI.JavaTypes,Androidapi.JNI.Telephony; var j: JSmsManager; begin j := tjsmsmanager.Create; j.sendTextMessage(stringtojstring('137114553XX'), nil, stringtojstring('测试短信'), nil, nil); end; 至于双卡双待用哪个卡来发送这些我没有详细研究,有兴趣的朋友可以研究下.

USACO08JAN Telephone Lines

荒凉一梦 提交于 2019-12-04 07:07:54
Luogu 分析 分层最短路模板题。 话说我卡了半天发现是 insert 函数写错了??? 代码 #include <queue> #include <cstdio> #include <cstring> #include <iostream> #include <algorithm> #define N 100001 #define il inline #define re register #define INF 0x3f3f3f3f #define tie0 cin.tie(0),cout.tie(0) #define fastio ios::sync_with_stdio(false) #define File(x) freopen(x".in","r",stdin);freopen(x".out","w",stdout) using namespace std; typedef long long ll; template <typename T> inline void read(T &x) { T f = 1; x = 0; char c; for (c = getchar(); !isdigit(c); c = getchar()) if (c == '-') f = -1; for ( ; isdigit(c); c = getchar()) x = x * 10

django登录、登出和使用限制

拟墨画扇 提交于 2019-12-03 23:35:44
用户登录、登出、登录限制 1、在app01/models.py里面定义User模型,通过AbstractBaseUser扩展用户模型 from django.db import models from django.contrib.auth.models import BaseUserManager, AbstractBaseUser, PermissionsMixin from django.contrib.auth import get_user_model class UserManager(BaseUserManager): def _create_user(self , telephone, username, password, **kwargs): if not telephone: raise ValueError("必须要传递手机号码!") if not password: raise ValueError("必须要传递密码") user = self.model( telephone = telephone, username= username , **kwargs) user.set_password( password ) user.save() return user def create_user(self, telephone, username,

「USACO08JAN」电话线Telephone Lines

空扰寡人 提交于 2019-12-03 13:16:38
传送门 Luogu 解题思路 考虑二分,每次把大于二分值的边的权设为1,小于等于的设为0,如果最短路<=k则可行,记得判无解 细节注意事项 咕咕咕 参考代码 #include <algorithm> #include <iostream> #include <cstring> #include <cstdlib> #include <cstdio> #include <cctype> #include <cmath> #include <ctime> #include <queue> #define rg register using namespace std; template < typename T > inline void read(T& s) { s = 0; int f = 0; char c = getchar(); while (!isdigit(c)) f |= (c == '-'), c = getchar(); while (isdigit(c)) s = s * 10 + (c ^ 48), c = getchar(); s = f ? -s : s; } const int _ = 1002; const int __ = 10002; int tot, head[_], nxt[__ << 1], ver[__ << 1], w[__ << 1];

多表操作查询

不问归期 提交于 2019-12-03 11:54:52
1. 表关系models from django.db import models class Author(models.Model): """ 作者表 """ name = models.CharField(max_length=32) age = models.IntegerField() sex = models.CharField(max_length=20, default='male') au = models.OneToOneField("AuthorDetail",on_delete=models.CASCADE) def __str__(self): return self.name class AuthorDetail(models.Model): """ 作者详细信息表 """ birthday = models.DateField() telephone = models.CharField(max_length=11) addr = models.CharField(max_length=64) # class Meta: # db_table='authordetail' #指定表名 # ordering = ['-id',] def __str__(self): return self.telephone + self.addr class

Catchable Fatal Error: Argument 1 passed to Doctrine\\Common\\Collections\\ArrayCollection::__construct() must be of the type array, object given

匿名 (未验证) 提交于 2019-12-03 09:52:54
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I'm learning Symfony 2 and I got the following error when I submit a form: Catchable Fatal Error: Argument 1 passed to Doctrine\Common\Collections\ArrayCollection::__construct() must be of the type array, object given, called in C:\xampp\htdocs\ppe2\vendor\doctrine\orm\lib\Doctrine\ORM\UnitOfWork.php on line 555 and defined Here is my code : Controller : public function ajouterAction(Request $request){ $sponsor = new Sponsor(); $formulaire = $this->createForm(new SponsorType(), $sponsor)->add('Ajouter', 'submit'); if ($formulaire-

AttributeError: &#039;NoneType&#039; object has no attribute &#039;get_text&#039;

匿名 (未验证) 提交于 2019-12-03 02:23:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I am parsing HTML text with Telephone = soup.find(itemprop="telephone").get_text() In the case a Telephone number is in the HTML after the itemprop tag, I receive a number and get the output ( "Telephone Number: 34834243244" , for instance). Of course, I receive AttributeError: 'NoneType' object has no attribute 'get_text' in the case no telephone number is found. That is fine. However, in this case I would like Python not to print an error message and instead set Telephone = "-" and get the output "Telephone Number: -" . Can anybody advise

bzoj 1705: [Usaco2007 Nov]Telephone Wire 架设电话线【dp】

匿名 (未验证) 提交于 2019-12-03 00:32:02
i的初始化写成2了于是成功查错2h……怕不是个傻子 设f[i][j]为第i根高为j,转移是 \[ f[i][j]=min(f[i-1][k]+abs(k-j)*c+(j-h[i])^2)(j>=h[i],k>=h[i-1]) \] 时间复杂度是1e5*1e2*1e2,空间复杂度是1e5*1e2,显然都过不了 abs很碍眼,所以考虑分两种情况,化简之后就是 \[ f[i][j]=min(f[i-1][k]+k*c)-j*c+(j-h[i])^2(j>=h[i],k>=h[i-1],k>=j) \] \[ f[i][j]=min(f[i-1][k]-k*c)+j*c+(j-h[i])^2(j>=h[i],k>=h[i-1],k<j) \] 然后另开数组ad[i][j]表示i根从j到100最大的f[i][j]+j c,mi[i][j]表示i根从a[i]到j最大的f[i][j]-j c,这个可以在求完f[i][]之后直接扫一遍求出,这样时间复杂度就降为了1e5*1e2 然后发现f,ad,mi的i维都没用,所以直接推掉,空间复杂度就变成了1e2(还有1e5的h数组) 就没了 #include<iostream> #include<cstdio> #include<algorithm> using namespace std; const int N= 100005 ,inf= 1e9 ;

使用maven搭建Hibernate

时光毁灭记忆、已成空白 提交于 2019-12-01 17:11:03
使用maven搭建Hibernate框架(web项目) 1 create table USERS 2 ( 3 ID NUMBER not null primary key, 4 NAME VARCHAR2(50), 5 PASSWORD VARCHAR2(50), 6 TELEPHONE VARCHAR2(15), 7 USERNAME VARCHAR2(50), 8 ISADMIN VARCHAR2(5) 9 ); 10 create table DISTRICT 11 ( 12 ID NUMBER not null primary key, 13 NAME VARCHAR2(50) not null 14 ); 15 create table HOUSE 16 ( 17 ID NUMBER, 18 USER_ID NUMBER, 19 TYPE_ID NUMBER, 20 TITLE NVARCHAR2(50), 21 DESCRIPTION NVARCHAR2(2000), 22 PRICE NUMBER, 23 PUBDATE DATE, 24 FLOORAGE NUMBER, 25 CONTACT VARCHAR2(100), 26 STREET_ID NUMBER 27 ); 28 29 create table STREET 30 ( 31 ID NUMBER not

利用ajax,js以及正则表达式来验证表单递交

大城市里の小女人 提交于 2019-11-30 12:34:18
<!DOCTYPE html><html lang="en"> <head> <meta charset="utf-8"> <title>注册</title> <link rel="stylesheet" type="text/css" href="css/common.css"> <link rel="stylesheet" href="css/register.css"> <!--导入jquery--> <script src="js/jquery-3.3.1.js"></script> <script> //校验用户名 function checkUserName() { //1、获取控件username的值 var username = $("#username").val(); //2、定义正则表达式 var reg_username=/^\w{8,20}$/; //3、判断 var flag = reg_username.test(username); if(flag){ $("#username").css("border",""); }else{ $("#username").css("border","solid 1px red"); } return flag; } //校验密码 function checkPassword() { //1