closures

C++ COM Object Hotpatching?

房东的猫 提交于 2019-12-04 20:41:32
Background: I'm hooking on windows COM object. The method used is vtable modification. say we have an instance of interface A named instance , it contains oldmethod in the interface, I replaced with newmethod . However, in my newmethod I need to know the address of oldmethod so that I can call oldmethod after doing my own thing. It is not safe to store the address of oldmethod in a global variable, since there might be more than one implementation behind interface A , let's say there are two implementations, class A1 and class A2 . Thus my newmethod needs to store both A1->oldmethod and A2-

Wait to return from a javascript function until condition met

99封情书 提交于 2019-12-04 19:32:48
问题 This is an odd problem. I have a client object that I am building up using Crockford-esque public/private members: var client = function() { var that, remote_data, other_data; // add public interface that.doStuff = function(){...} // wait for remote resources to load remote_data = jsonRequest1(); other_data = jsonRequest2(); return that; }; The problem I'm having is that I need to load some remote JSON resources prior to returning the new 'that' object (which signals a ready client). Data is

Swift Selectors and Closures Discussion

喜夏-厌秋 提交于 2019-12-04 19:03:56
I searched a lot and haven't found anything that really helped to solve my problem... I'm trying to build a simple UIControl from scratch, like a UIButton. It can't be subclass of UIControl for particular reasons. I need this control to do something like this: myControl.addTarget(target: AnyObject?, action: Selector, forControlEvents: UIControlEvents) The problem is that the implementation of the method that execute this selector when the button is touched needs the "performSelector:" method. Swift doesn't have a "performSelector:". So I taught it could be implemented using closures. I couldn

Groovy: meaning of 'this' inside a closure

不羁岁月 提交于 2019-12-04 18:34:33
问题 The following example is adapted from 'Groovy in Action' class Mother { Closure birth() { def closure = { caller -> [this, caller] } return closure } } Mother julia = new Mother() closure = julia.birth() context = closure.call(this) println context[0].class.name // Will print the name of the Script class assert context[1] instanceof Script According to the book, the value of this inside the closure is the outermost scope (i.e. the scope in which julia is declared). Am I right in assuming that

Python's nonlocal depends on level of hierarchy?

蹲街弑〆低调 提交于 2019-12-04 18:32:16
问题 This question is a follow-up on a question about Python variable scope. Additional questions q1, q2 and answers can be found on SO, among even more. The official Python documentation, and PEP 3104 are supposed to explain the details, but they don't seem fully self-explanatory to me. The topic I'm trying to solve is refactoring of code containing nonlocal / global by moving that code up/down one level of hierarchy. What I do not understand are the implications of this sentence from the Python

Extra parentheses on function [duplicate]

泄露秘密 提交于 2019-12-04 18:17:58
问题 This question already has answers here : Closed 7 years ago . Possible Duplicate: What do parentheses surrounding a JavaScript object/function/class declaration mean? What does this “(function(){});”, a function inside brackets, mean in javascript? A Javascript function I encountered markup similar to this: var something = (function(){ //do stuff return stuff; })() document.ondblclick = function(e) { alert(something(e)) }; I don't understand the opening ( and closing )() in the something

What is the point of OOP visibility in PHP when Closures and Reflections are available?

筅森魡賤 提交于 2019-12-04 17:38:26
问题 Consider this code here: final class TinkerWithMe { protected $key1 = 19; private $key2 = 88; } $class = new TinkerWithMe(); $getKeys = function() { return array($this->key1, $this->key2); }; $oldKeys = $getKeys->call($class); $newKey1 = 96; $newKey2 = 42; $setKeys = function() use ($newKey1, $newKey2) { $this->key1 = $newKey1; $this->key2 = $newKey2; }; $setKeys->call($class); Why bother with OOP visibility when you can get around it so easily with Closures or Reflections? Is there a way of

python counter with closure

你离开我真会死。 提交于 2019-12-04 17:36:42
I'm trying to build a counter in python with the property of closure. The code in the following works: def generate_counter(): CNT = [0] def add_one(): CNT[0] = CNT[0] + 1 return CNT[0] return add_one However when I change the list CNT to a var, it did not work: def generate_counter1(): x = 0 def add_one(): x = x + 1 return x return add_one when I print the closure property of an instance, I found the __closure__ of the second case is none: >>> ct1 = generate_counter() >>> ct2 = generate_counter1() >>> print(ct1.__closure__[0]) <cell at 0xb723765c: list object at 0xb724370c> >>> print(ct2._

Is there a way to make this slideshow move automatically?

故事扮演 提交于 2019-12-04 16:21:08
This is the slideshow that we used: http://www.littlewebthings.com/projects/blinds/ and this is the JS file: http://www.littlewebthings.com/projects/blinds/js/jquery.blinds-0.9.js However, this slideshow doesn't have a setting that makes it go through each image automatically. You still have to click on the numbers below it to see the images. Does anybody know what to add into the javascript code to make it go through each image automatically? Thanks! This solution uses closures and recursion. var SlideChanger = function(seconds_each) { var index = -1; // on the first cycle, index will be set

Why Don't Variables Reset in a Closure (Javascript)

自闭症网瘾萝莉.ら 提交于 2019-12-04 15:41:19
I've been trying to learn about closures, but one thing still perplexes me. If I have the following code: var add = (function () { var counter = 0; return function () {return counter += 1;} })(); add(); add(); add(); // Returns "3" If I call add() three times, why dosen't it set counter to zero every time, then return the anonymous funtion that increments counter by one? Does it skip over it once the self-invoking function runs? Sorry if the question seems simple, I'm having a hard time understanding it. Any help would be greatly appreciated. If I call add() three times, why dosen't it set