a10

于是我拿24c08来讲一下，从pdf上我们了解到在IIC总线最多有2 个atc08，这正是A2 的作用，A2=0或1分别对应着器件1和器件2. 那24c08里的a9和a8是什么用呢？看下面的这段英文（从英文的 paf下摘下来的），你会明白了。 The 8K EEPROM only uses the A2 device address bit with the next 2 bits being formemory page addressing. The A2 bit must compare to its corresponding hard-wiredinput pin. The A1 and A0 pins are no connect. a9和a8是进行页选择的，a9和a8有4种组合，那就说有4页，每页有8kbits/4=2kbits=2000/8bytes=256bytes 每页有256bytes，需要a9和a8来选择读写哪一页。 明白了吗？ 1K 地址空间 ，由外部 A2 和内部 存储阵列 A9A8决定地址，例如你的 A2 固定接地，那么1K的存储空间分成4块，器件写地址分别是#0A0H,#0 A2 H,#0A4H,#0A6H,器件读地址是#0A1H,#0A3H,#0A5H,#0A7H，每个地址都对应256个字节。正好是8位地址00H--FFH

/home/yueyao/bio/anaconda2/bin/java -jar /home/yueyao/bio/anaconda2/share/picard-2.14.1-0/picard.jar MarkDuplicates I=/home/yueyao/11.BSA/outdir/04.preresult/L-pool/A10/L-pool.A10.sort.rg.bam O=/home/yueyao/11.BSA/outdir/04.preresult/L-pool/A10/L-pool.A10.mark.dup.bam M=/home/yueyao/11.BSA/outdir/04.preresult/L-pool/A10/L-pool.A10.mark.dup.metrics VALIDATION_STRINGENCY=SILENT 解决办法 /home/yueyao/bio/anaconda2/bin/java -jar /home/yueyao/bio/anaconda2/share/picard-2.14.1-0/picard.jar MarkDuplicates I=/home/yueyao/11.BSA/outdir/04.preresult/L-pool/A10/L-pool.A10.sort.rg.bam O=/home/yueyao/11.BSA