2d

问题 I am trying to make a simple ball animation, that starts from 1 corner and goes to another corner of the panel. I have written a program for that. When I run the program the oval or ball leaves the trail. What I mean to say is that it leaves it's 'color trail' when the program runs. In my program timer fires an event every 100 milliseconds. The following is the logic responsible for running the code : void function() { // in this there is a action listener timed accordingly to fire event of /

问题 Suppose I have 2D array as follow: int[][] temp={ {1,2,3,4}, {5,6,7,8}, {9,10,11,12}}; and i want to get sub-array start from X direction 1 to 2 and Y direction 1 to 2 i.e. {6,7} {10,11} can anyone give me solution for above problem. 回答1: Here you are int[][] temp = { { 1, 2, 3, 4 }, { 5, 6, 7, 8 }, { 9, 10, 11, 12 } }; int[][] a = new int[temp.length][]; for (int i = 0; i < temp.length; i++) { a[i] = Arrays.copyOfRange(temp[i], 1, 3); } System.out.println(Arrays.deepToString(a)); output [[2,

问题 Are there any new options for converting a spritekit game to android? It seems the only options are to recode everything in Java or to use Cocos2D, LibGDX, etc. 回答1: Unfortunately ... no :{ And the cross-platform SpriteBuilder with the Apportable service that let you convert a Swift Cocos project to Android is no longer available (they got bought out by Google I believe). SpriteBuilder is still available on GitHub but it's not active afaik and is abandoned. So... what to do? I would focus on

问题 I need to write an application for images morphing, but I can't use any libraries. I need to write my own. Can you tell me what algorithms are the best for that? 来源： https://stackoverflow.com/questions/14549400/morphing-3-algorithms-image-processing

问题 some of you know how fill a quads in 2D using barycentric coordinates?At the present, I'm splitting the quads into 2 triangles, but that way is inefficient because I have to iterate over the second bounding box which repeats pixel that were filled previously (by example, to fill the 2nd triangle I traversed the 1st triangle that belongs at bounding box formed by 2nd triangle) Thanks esmitt 回答1: Here is a python example that should be what you're looking for. As you probably know there are no

问题 Passing a fixed 2D array between C++ and Fortran works fine, however not so with the program I have written to pass a 2D dynamic array from C++ to Fortran. C++ side extern "C" {void array2d_(double **, int *, int *); } using namespace std; int main() { double **array; int nx=3; int ny=2; int i,j; cout << "Passing dynamic array from C to Fortran\n"; array = (double **) malloc(nx * sizeof(double *)); if(array == NULL) { fprintf(stderr, "out of memory\n"); exit; } for(i = 0; i < nx; i++) { array

问题 For specific reasons, I'm implementing my own font rendering, and an algorithm to compute the bounding box of a text by using bounding boxes of single glyphs, together with the respective advance, is needed. For clarification see this illustration: For every of these N glyphs is given the relative bbox relative to the origin (xmin, xmax, ymin, ymax), and the advance (pseudocode): int xmin[N], xmax[N], ymin[N], ymax[N], adv[N]; I will give the answer myself if noone bites. 回答1: For the general

问题 I'm working on a simple 2D Real time strategy game using XNA. Right now I have reached the point where I need to be able to click on the sprite for a unit or building and be able to reference the object associated with that sprite. From the research I have done over the last three days I have found many references on how to do "Mouse picking" in 3D which does not seem to apply to my situation. I understand that another way to do this is to simply have an array of all "selectable" objects in

问题 The initial problem: for a given 3x3 tic tac toe board check if one of the players has won. The simplest solution I have come up so far is rotating the matrix and summing up each row: board [[0, 1, 2], [3, 4, 5], [6, 7, 8]] pr(board) 0 1 2 3 4 5 6 7 8 pr(zip(*board)) 0 3 6 1 4 7 2 5 8 0..9 numbers above are just for showing positions on the board, normally they would be filled with 1 for player 1 and -1 for player 2 and 0 for unfilled position. Go row by row and if it sums up to 3 or -3 this

问题 I'm trying to create a 2D game engine for an Android app. I've followed this tutorial, which works fine for creating a full screen display, but I don't want that. I want to make my view take the top 2/3 (or whatever) of the screen, and fill the bottom third with standard Android widgets (buttons, text entry, etc.). I cannot get this to work. The best I can get is a blank white screen. I've tried many permutations, including using an outer LinerLayout, then embedding the custom SurfaceView