QueryDsl - subquery in collection expression

陌路散爱 提交于 2019-12-18 10:55:43

问题


I'm using spring-data-jpa and querydsl (3.2.3)
I have a scenario where I'm creating set of predicates based on user filer/input. All of these comes to BooleanExpression.

My simplified model looks as following:

@Entity
public class Invoice {
    @ManyToOne
    private Supplier supplier;
}

@Entity
public class Supplier {
    private String number;
}

@Entity
public class Company {
    private String number;
    private boolean active
}

Now, what I'm struggling with is this query:

SELECT * FROM Invoice WHERE invoice.supplier.number in (SELECT number from Company where active=true)

So basically I need to subquery in CollectionExpression like format that will fetch all companies numbers and sets this into in() expression.

My spring-data repositories implements CustomQueryDslJpaRepository which in turn extends JpaRepository and QueryDslPredicateExecutor.
I hope the answer to this is straightforward, but I'm quite new to querydsl and didn't find the solutions so far.


回答1:


Here is a variant of jaiwo99's answer in a more JPAesque form

BooleanExpression exp = invoice.supplier.number.in(new JPASubQuery()
    .from(company)
    .where(company.active.isTrue())
    .list(company.nu‌​mber));

Feel free to merge this into the original answer.




回答2:


Try this:

QInvoice invoice = QInvoice.invoice;
QCompany company = QCompany.company;

List<Invoice> list = new HibernateQuery(sessionFactory.getCurrentSession())
      .from(invoice).where(
      new HibernateSubQuery().from(invoice, company).where(
              invoice.supplier.number.eq(company.number).and(
              company.active.eq(true))).exists()).list(invoice);


来源:https://stackoverflow.com/questions/21826773/querydsl-subquery-in-collection-expression

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