I am wondering if there is a better to represent a fix amount of repeats in a regular expression. For example, if I just want to match exactly 14 letters/digits, I am using
The finite repetition syntax uses {m,n} in place of star/plus/question mark.
From java.util.regex.Pattern:
X{n} X, exactly n times
X{n,} X, at least n times
X{n,m} X, at least n but not more than m times
All repetition metacharacter have the same precedence, so just like you may need grouping for *, +, and ?, you may also for {n,m}.
ha* matches e.g. "haaaaaaaa"ha{3} matches only "haaa"(ha)* matches e.g. "hahahahaha"(ha){3} matches only "hahaha"Also, just like *, +, and ?, you can add the ? and + reluctant and possessive repetition modifiers respectively.
System.out.println(
"xxxxx".replaceAll("x{2,3}", "[x]")
); "[x][x]"
System.out.println(
"xxxxx".replaceAll("x{2,3}?", "[x]")
); "[x][x]x"
Essentially anywhere a * is a repetition metacharacter for "zero-or-more", you can use {...} repetition construct. Note that it's not true the other way around: you can use finite repetition in a lookbehind, but you can't use * because Java doesn't officially support infinite-length lookbehind.
a{1}b{0,1} instead of ab?In Java create the pattern with Pattern p = Pattern.compile("^\\w{14}$"); for further information see the javadoc
^\w{14}$ in Perl and any Perl-style regex.
If you want to learn more about regular expressions - or just need a handy reference - the Wikipedia Entry on Regular Expressions is actually pretty good.
For Java:
Quantifiers documentation
X, exactly n times: X{n}
X, at least n times: X{n,}
X, at least n but not more than m times: X{n,m}