java foreach skip first iteration

Question

Is there an elegant way to skip the first iteration in a Java5 foreach loop ?

Example pseudo-code:

for ( Car car : cars ) {     
   //skip if first, do w         


        

Answer 1

Elegant? Not really. You'd need to check/set a boolean.

The for-each loop is for all practical purposes fancy syntax for using an iterator. You're better off just using an iterator and advancing before you start your loop.

Answer 2

I came a bit late to this, but you could use a helper method, something like:

public static <T> Iterable<T> skipFirst(final Iterable<T> c) {
    return new Iterable<T>() {
        @Override public Iterator<T> iterator() {
            Iterator<T> i = c.iterator();
            i.next();
            return i;
        }
    };
}

And use it something like this:

public static void main(String[] args) {
    Collection<Integer> c = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9);
    for (Integer n : skipFirst(c)) {
        System.out.println(n);
    }
}

Generalizing to skip "n" is left as an exercise for the reader :)

---

EDIT: On closer inspection, I see that Guava has an Iterables.skip(...) here.

Answer 3

Not so elegant but work with iterators

Iterator<XXXXX> rows = array.iterator();
if (rows.hasNext()){
    rows.next();
}
for (; rows.hasNext();) {
    XXXXX row = (XXXXX) rows.next();
}

Answer 4

for (Car car : cars)
{
   if (car == cars[0]) continue;
   ...
}

Elegant enough for me.

Answer 5

I'm not a java person but can you use :

for ( Car car : cars.tail() ) from java.util via Groovy JDK

Answer 6

I wouldn't call it elegant, but perhaps better than using a "first" boolean:

for ( Car car : cars.subList( 1, cars.size() ) )
{
   .
   .
}

Other than that, probably no elegant method.