Say we have a Map: let m = new Map();, using m.values() returns a map iterator.
But I can\'t use forEach() or map() o         
        
The simplest and least performant way to do this is:
Array.from(m).map(([key,value]) => /* whatever */)
Better yet
Array.from(m, ([key, value]) => /* whatever */))
Array.from takes any iterable or array-like thing and converts it into an array! As Daniel points out in the comments, we can add a mapping function to the conversion to remove an iteration and subsequently an intermediate array.
Using Array.from will move your performance from O(1) to O(n) as @hraban points out in the comments. Since m is a Map, and they can't be infinite, we don't have to worry about an infinite sequence. For most instances, this will suffice.
There are a couple of other ways to loop through a map.
forEachm.forEach((value,key) => /* stuff */ )
for..ofvar myMap = new Map();
myMap.set(0, 'zero');
myMap.set(1, 'one');
for (var [key, value] of myMap) {
  console.log(key + ' = ' + value);
}
// 0 = zero
// 1 = one
                                                                        You could use itiriri that implements array-like methods for iterables:
import { query } from 'itiriri';
let m = new Map();
// set map ...
query(m).filter([k, v] => k < 10).forEach([k, v] => console.log(v));
let arr = query(m.values()).map(v => v * 10).toArray();