Properly indent the code (I used http://beta.phpformatter.com/)
http://pastebin.com/A106eFjY
Look for function calls (func() or $func()).
Line 14: `$eva1tYldokBcVSjr(..., $eva1tYldakBcVSir(...));
Comment out the function call, and echo $eva1tYldokBcVSjr (and $eva1tYldakBcVSir) to see what it's doing.
echo $eva1tYldokBcVSjr; => 'preg_replace'
echo $eva1tYldakBcVSir;=> 'strrev'
echo out the parameters passed to $eva1tYldokBcVSjr() (preg_replace()).
$eva1tYidokBcVSjr[0.016 * (7812.5 * 0.016)] => "@(.+)@ie"
$eva1tYidokBcVSjr[62.5 * 0.016] => "eval("\1");"
strrev($eva1tYidokBcVSjr[0.061 * 0.031]) => "@eval(base64_decode($eva1tYidakBcVSjr[1]));"
So line 14 decodes to (in a PHP regex anything can be a delimiter):
preg_replace("/(.+)/ie", 'eval("\1");', eval(base64_decode($eva1tYidakBcVSjr[1])));
The string that's being base64_decoded decodes to code with a bunch of evals in it.
http://pastebin.com/zRr9dMHN
Replace all those evals with echos, to see what's going on. There are even more eval(base64_decode(s.
http://pastebin.com/H9WcBFyJ
Changing those evals to echos gets you this:
http://pastebin.com/VaYCgUyK
I see a setcookie in there...
EDIT: Here's a post where someone continued decoding this:
http://www.thehosthelpers.com/technical-help/help-de-obfsucating-code/msg17585#msg17585