Use OR within if else condition by inverse condition order in php

Question

I am trying to get \"OK\" if my condition False, i want to keep same if else order as given example, don\'t advice to move \"else\" content in \"if\" and \"if\" content in \"els

Answer 1

I tested this code and it works.

if(!($flag != 0 || $point >= 1000)){
    echo "Not OK";
}else{
    echo "OK";
}

Answer 2

After reading your comments:

It seems you want to show some score (in the else-branch of an if-then-else) if the user has equal/more than 1000 points or you toggle a flag (which basically means "always show points").

Normally you'd be doing that in the if-branch:

if ($flag || $point >= 1000)
{
    echo "OK";
} else {
    echo "Not OK";
}

Since you want the Not OK to be in the if-Branch you need to inverse the condition, doing so means inverting every part of the condition and the operators aswell:

• $flag becomes !$flag
• $point >= 1000 becomes $point < 1000
• || becomes &&

Result:

if (!$flag && $point < 1000)
{
    echo "Not OK";
} else {
    echo "OK";
}

Writing this into a truth-table:

flag        point       result
0           < 1000      Not OK
1           < 1000      OK
0           >=1000      OK
1           >=1000      OK