C++: too few arguments in function call [closed]

Answer 1

Your problem is here:

compute_duplicate((x,(y+1), array, array_length)==false))

I.e. you are trying to call compute_duplicate with one argument of type bool, which is the result of the valid expression (x,(y+1), array, array_length)==false. Note that comma is an operator in C/C++, so the effective result of the expression above is array_length==false.

What is probably meant is:

compute_duplicate(x,(y+1), array, array_length)==false

Answer 2

The following function call has a misplaced bracket

compute_duplicate((x,(y+1), array, array_length)==false)

it should be

(compute_duplicate(x,(y+1), array, array_length)==false)

the same error exists in two places within your loop.

Answer 3

compute_duplicate((x,(y+1), array, array_length)==false) is calling compute_duplicate with one argument, the result of (x,(y+1), array, array_length)==false.

Did you mean (compute_duplicate(x,(y+1), array, array_length)==false) ?

(Just a slightly different arrangement of ()s but a very different piece of C++.

Answer 4

compute_duplicate((x,(y+1), array, array_length)==false)) is calling compute_duplicate on the expression (x,(y+1), array, array_length)==false), which is a single boolean value that is true if and only if (x,(y+1), array, array_length) is false. This is not what you want.

Answer 5

An extra pair of braces here:

compute_duplicate((x,(y+1), array, array_length)==false)

Makes the compiler think you pass a single bool as argument. Loose them and error should be fixed.