Sort the age of 3 individuals [closed]

Answer 1

less ifs if you use the variable

#define swap(a,b)    do { int c = (a); (a) = (b); (b) = (c);} while(0)
if (age[2] > age[1]) swap(age[2], age[1]);
if (age[1] > age[0]) swap(age[1], age[0]);
if (age[2] > age[1]) swap(age[2], age[1]);

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or

if (age2 > age1) swap(age2, age1);
if (age1 > age0) swap(age1, age0);
if (age2 > age1) swap(age2, age1);

Answer 2

In your code

 if (age1==age2==age3);

is horribly broken.

Two main points,

• An expression like age1==age2==age3 is either

  • 0 == age3 , when age1 != age2
  • 1 == age3 , when age1 == age2

  none of which is you want.

• The ; at the end of the if statement makes the next block unconditional.

At best, you can rewrite the same as

 if ( ( age1 == age2 ) && ( age2 == age3) ) { .... }

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After that, in case of

  printf("All individuals have the same age of %d", &age1);

you don't need to pass the address-of the variable. This, in fact makes the statement very wrong, passing an incompatible type of argument to a supplied conversion specifier, which causes undefined behavior.