sumifs function in python

Question

I have a list of lists that looks like:

[[\'chr1\', \'3088\', \'1\', 744, \'L1MCc_dup1\']
[\'chr1\', \'3089\', \'1\', 744, \'L1MCc_dup1\']
[\'chr1\', \'3090\', \         


        

Answer 1

Use a dictionary:

d = {}
for row in my_list:
    key = row[4]
    value = int(row[2])
    d[key] = d.get(key, 0) + value

After this loop, d will map the key values in the last column to the desired sums.

You could also use collections.defaultdict instead of a normal dictionary.

Answer 2

>>> d =[['chr1', '3088', '1', 744, 'L1MCc_dup1'],
['chr1', '3089', '1', 744, 'L1MCc_dup1'],
['chr1', '3090', '1', 744, 'L1MCc_dup1'],
['chr1', '15037', '1', 96, 'MER63B'],
['chr1', '15038', '1', 96, 'MER63B'],
['chr1', '15039', '1', 96, 'MER63B'],
['chr1', '15040', '1', 96, 'MER63B'],
['chr1', '19465', '1', 418, 'MLT2B4_dup1'],
['chr1', '19466', '1', 418, 'MLT2B4_dup1'],
['chr1', '19467', '1', 418, 'MLT2B4_dup1']]
>>> sum(map(lambda x: x[3], filter(lambda x: x[4] == 'MLT2B4_dup1', d)))
1254

Sum of all column 4 values (I assume you meant that because it was the only int column), where the last column equals to 'MLT2B4_dup1'. You can change that to any other condition of course.