bad operand types for binary operator >=, -, *

Question

I\'m having trouble figuring out how to fix these errors I keep getting for my code

import java.util.Scanner;

public class Unit02Prog1 {

    public static void         


        

Answer 1

In this situation you need parse from string to integer. Here you have an example:

String simplenumber= "10";
int num = Integer.parseInt(simplenumber);

In your code:

public static void main(String[] args) { Scanner input = new Scanner(System.in);

    String name;
    System.out.print("name");
    name = input.next();

    String catagory;
    System.out.print("Catagory");
    catagory = input.next();

    String numWords;
    System.out.print("numWords");
    numWords = input.next();

    int price;
    int numWordsInt = Integer.parseInt(numWords);

    if (numWordsInt >= 50) {
        price = (int) (((numWordsInt -50) * .08) + 5.00);
        System.out.println("customer:" + name);
        System.out.println("Placed an ad in catagory:" + catagory);
        System.out.println("Ad length is" + numWords + "words, at a price of $" + price);
    }
    else {
        price = (int) (numWordsInt * .10);
        System.out.println("customer:" + name);
        System.out.println("Placed an ad in catagory:" + catagory);
        System.out.println("Ad length is" + numWords + "words, at a price of $" + price);
    }}

Answer 2

What you are doing wrong

if (numWords >= 50) {

numWords is a string, and >= only works on numbers.

How to fix

You have 2 options for fixing this:

• Read the number in as a String and convert it to a number

  temp = input.nextLine();
  numWords = Integer.parseInt(temp);
  

  This way means you can check manually, and do not need to catch an exception if the number is wrong.

• Read the number in as a number straight away

  numWords = input.nextInt();
  

  This way is less code, but you will need to catch a NumberFormatException if the input is not an integer.

Other notes

• You use input.next() a lot, depending on your inputs you may want to use nextLine instead
• You may want to use System.out.printf to clean up your printing code

Answer 3

your variable numWords is string, please parse it to integer first for comparing. Then, update price to double as well. Sample code is as per below.

    int numWords;
    System.out.print("numWords");
    numWords = input.nextInt();

    double price;

    if (numWords >= 50) {
        price = ((numWords -50) * .08) + 5.00;
        System.out.println("customer:" + name);
        System.out.println("Placed an ad in catagory:" + catagory);
        System.out.println("Ad length is" + numWords + "words, at a price of $" + price);
    }

Answer 4

numWords is a String, not an int. Parse the String to get an int.

int num_words = Integer.parseInt(numWords);