Objects.deepToString(Object o) method

Question

The class java.util.Objects contains the deepEquals(Object a, Object b) method that can be used to compare objects of any type (including arrays and nu

Answer 1

I came to this solution: wrap a primitive array into Object[] and remove the outer brackets from the result returned by the public Arrays.deepToString(Object[] a):

public static String deepToString(Object o) {
    if (o == null || !o.getClass().isArray())
        return Objects.toString(o);
    else if (o instanceof Object[])
        return Arrays.deepToString((Object[])o);
    else {
        String s = Arrays.deepToString(new Object[] { o });
        return s.substring(1, s.length() - 1);
    }
}

Not very efficient, because it could create two large strings instead of a single one. But with this trick, I can use the hidden

Arrays.deepToString(Object[] a, StringBuilder buf, Set<Object[]> dejaVu)

method that contains the primitive arrays parsing logic.