Unexpected update result on the quickly nested list in Python [duplicate]

Answer 1

Even tho this is a clear duplicate but use range:

>>> x=[[1 for i in range(2)] for x in range(2)]
>>> x
[[1, 1], [1, 1]]
>>> x[0][0]=2
>>> x
[[2, 1], [1, 1]]
>>> 

At least still able to do:

>>> x=[[1]*2 for x in range(2)]
>>> x[0][0]=2
>>> x
[[2, 1], [1, 1]]
>>>