I have this block of code that reliably creates a string object. I need to write that object to a file. I can print the contents of \'data\' but I can\'t figure out how to write
with open (template_file, "r") as a_string:
   data=a_string.read().replace('{SERVER_NAME}', server_name).replace('{BRAND}', brand).replace('{CONTENT_PATH}', content_path).replace('{DAMPATH}', dampath).replace('{ENV}', env).replace('{CACHE_DOCROOT}', cache_docroot).replace('{SLD}', sld)
filename = "{NNN}_{BRAND}_farm.any".format(BRAND=brand, NNN=nnn)
with open(filename, "w") as outstream:
    outstream.write(data)
I can print the contents of 'data' but I can't figure out how to write it to a file as output
Use with open with mode 'w' and write instead of read:
with open(template_file, "w") as a_file:
   a_file.write(data)
Also why does "with open" automatically close a_string?
open returns a File object, which implemented both __enter__ and __exit__ methods. When you enter the with block the __enter__ method is called (which opens the file) and when the with block is exited the __exit__ method is called (which closes the file).
You can implement the same behavior yourself:
class MyClass:
    def __enter__(self):
        print 'enter'
        return self
    def __exit__(self, type, value, traceback):
        print 'exit'
    def a(self):
        print 'a'
with MyClass() as my_class_obj:
     my_class_obj.a()
The output of the above code will be:
'enter'
'a'
'exit'