Second touch animation

Question

Trying to get to grips with Xcode and seem to be making some progress over the last few weeks.

Does anyone know a way that a custom button can do a different set of anim

Answer 1

Use the selected state of the button to decide which animation to do

-(void)buttonClicked:(UIButton*)button
{
     if(button.selected)
     {
          [self doAnimation1];
     }
     else
     {
          [self doAnimation2];
     }

     button.selected = !button.selected;
}

Answer 2

This might be overkill, but here's a cool way to do what you want:

Make a subclass of UIButton, and let's call it DDDMarioButton:

typedef void (^DDDAnimationBlock)(UIButton *button);

@interface DDDMarioButton : UIButton

- (void)addAnimationBlockToQueue:(DDDAnimationBlock)block;

@end

Then in DDDMarioButton.m:

@interface DDDMarioButton ()

@property (nonatomic, strong) NSMutableArray *animationQueue;

@end

@implementation DDDMarioButton

- (id)initWithFrame:(CGRect)frame
{
    self = [super initWithFrame:frame];
    if (self) {
        [self addTarget:self action:@selector(buttonPressed:) forControlEvents:UIControlEventTouchUpInside];
    }
    return self;
}

- (void)buttonPressed:(id)button
{
    DDDAnimationBlock block = self.animationQueue[0];
    block(self);
    [self.animationQueue removeObjectAtIndex:0];
}

- (void)addAnimationBlockToQueue:(DDDAnimationBlock)block
{
    if(!self.animationQueue)
    {
        self.animationQueue = [NSMutableArray new];
    }

    [self.animationQueue addObject:block];
}

@end

and then wherever you create your buttons, you add each step one by one:

DDDMarioButton *button = [[DDDMarioButton alloc] initWithFrame:CGRectZero];

[button addAnimationBlockToQueue:^(UIButton *button) {
   // perform some animation
}];

[button addAnimationBlockToQueue:^(UIButton *button) {
    // perform another animation
}];

And that should do it. I haven't tested this, you'll probably need some configuration, but that's pretty much the idea.