Extract character before and after “/”

Question

I\'m trying to extract character before and after \"/\" with no success. Sentences are:

XXXX YYY ZZZ - AV HAHEHRS, 3061 - SDDW ASDA DDSF - SAO JOSE DOS CAMPOS /          


        

Answer 1

In your regex there is the space missing. Try:

str_extract(str, "- [a-zA-Z ]+ / [a-zA-Z ]+") 

Note the space in the character class. Also, {1,} is the long form of +.

The match will be "- SAO JOSE DOS CAMPOS / SP - CEP". You must get rid of the - in a second step, or use a zero-width look-behind:

str_extract(str, "(?<=- )[a-zA-Z ]+ / [a-zA-Z ]+") 

Look-behinds are supported by gregexpr.

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For the sake of completeness, you could do this without regex: Split the input by '-', find the part that contains '/', trim. This might be faster than regex, too.