Why is this simple piece of code not working?

Question

I am trying to get a floating variable accurate to just 3 decimal points for a comparison calculation. I am trying the method below, but it doesn\'t work. I can\'t see why not,

Answer 1

When you perform

 fbb = bb/1000;

It treats operation as int/int and returns an int

Try

fbb = ((double)bb)/1000.000;

It will be treated as (double)/(double) and return a double.

Answer 2

When you perform

fbb = bb/1000;

It treats operation as int/int and returns an int. its demotion of value.

Also take long bb; instead of int as int has value 32767 as its high value.

Try

fbb = bb/1000.000;

or

fbb = (double)bb/1000;

Answer 3

bb is int. So bb/1000 is doing a int division, which results again in an int = 1000 (no decimals). That int value is cast to a double.

Answer 4

bb is an int, so bb / 1000 will follow the integer division. Change either or both operand to a double. The simplest way is:

fbb = bb / 1000.0;       //type of 1000.0 is double

or

fbb = (double)bb / 1000

Answer 5

Use

fbb=(double)bb/1000;

bb is integer and result is integer, and then converted to double