Using regex to remove all text after the last number in a string

Question

Sample Text

1234 Main St Smallville, KS 92348Small County 

Should yield:

1234 Main St Smallville, KS 92348

Sa

Answer 1

Find the last digit in the string and then remove all the characters after it with re.sub:

import re
address = "1234 Main St Smallville, KS 92348Small County "
address = re.sub(r'(\d)\D+$', r'\1', address)
print(address) # => 1234 Main St Smallville, KS 92348

See the IDEONE demo

The regex matches and captures into Group 1 a digit (with (\d)) and then matches one or more characters other than a digit (\D+) up to the end of the string ($). The replacement pattern is a mere \1, a backreference to the digit we captured with Group 1 (to restore it in the resulting string).

Answer 2

You can use greedy .* before \d+ to make sure to match upto last digits:

>>> print re.findall(r'^(.*\d+).*$', address)[0]
1234 Main St Smallville, KS 92348

Regex Demo