Is there one-line syntax for constructing a struct that contains a reference to a temporary?

Question

Consider the following invalid Rust code. There is one struct Foo that contains a reference to a second struct Bar:

struct Foo<\'a&g         


        

Answer 1

No, there is no such syntax, other than what you have typed.

For the details of how long a temporary lives when you take a reference to it, see:

• Why is it legal to borrow a temporary?

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There will be a parent struct owning both the bar and the foos referencing it.

Good luck:

• Why can't I store a value and a reference to that value in the same struct?