Simple bash script; what's wrong with this syntax?

Question

I\'m reading bash script tutorials and this seems like it should work, but I clearly am missing something:

isframecount=0
framecount=0
while read p; do
  if [\"$         


        

Answer 1

if [ "$isframecount" -eq 0 ]

Spaces are required on both sides of the square brackets.

isframecount=1

No dollar sign, no spaces around = in an assignment statement.

Answer 2

Watch out for spaces where they matters and where there should be not. In this case, if ["$isframecount" -eq 0] should be if [ "$isframecount" -eq 0 ] (see the spaces after [ and before ]).

The reason for this is that [ is actually the name of a program... See by yourself... Type ls /bin/[... Now, if there is no space, then bash will look for a program named ["0" or something similar, which most certainly does not exist in your path.

Then, the opposite situation... There must be no space around the = in variable assignment. So $isframecount = 1 should be isframecount=1. Note that I also removed the dollar sign, that's the way to go.

Answer 3

Two issues:

Issue 1:

You need to have spaces in test operator. Change the following line:

if ["$isframecount" -eq 0]

to

if [ "$isframecount" -eq 0 ]

Issue 2:

$isframecount = 1

There should be no $ sign before variable and no spaces in the assignment operator

Change it to isframecount=1