#include
#include
#include
#include
#include
int main(int argc, string argv[])
{
if (ar
I believe the problem is in
isdigit (argv[1])
argv[1] is of type char *, but isdigit() expects an int.
If you want to check whether the supplied argument is all-numerical value or not, you have to either
argv[n] and pass them one by one to isdigit() check.The error in on line 13, You need to do a
...
13: if (isdigit (atoi(argv[1])) != 0)
...