Remove text between square brackets at the end of string

Question

I need a regex to remove last expression between brackets (also with brackets)

source: input[something][something2] target: input[something]

I\'ve tried this, bu

Answer 1

Note that \[.*?\]$ won't work as it will match the first [ (because a regex engine processes the string from left to right), and then will match all the rest of the string up to the ] at its end. So, it will match [something][something2] in input[something][something2].

You may specify the end of string anchor and use [^\][]* (matching zero or more chars other than [ and ]) instead of .*?:

\[[^\][]*]$

See the JS demo:

console.log(
   "input[something][something2]".replace(/\[[^\][]*]$/, '')
);

Details:

• \[ - a literal [
• [^\][]* - zero or more chars other than [ and ]
• ] - a literal ]
• $ - end of string

Another way is to use .* at the start of the pattern to grab the whole line, capture it, and the let it backtrack to get the last [...]:

console.log(
   "input[something][something2]".replace(/^(.*)\[.*]$/, '$1')
);

Here, $1 is the backreference to the value captured with (.*) subpattern. However, it will work a bit differently, since it will return all up to the last [ in the string, and then all after that [ including the bracket will get removed.

Answer 2

Do not use the g modifier, and use the $ anchor:

"input[something][something2]".replace(/\[[^\]]*\]$/, '');

Answer 3

try this code

var str = "Hello, this is Mike (example)";

alert(str.replace(/\s*\(.*?\)\s*/g, ''));