Getline problem [duplicate]

Answer 1

If you have a cin >> something; call prior to your system() call.

For example, taking input into an integer. When cin >> myintvar; (or similar) then the integer is placed in myintvar and the '\n' gets sent along in the stream. The getline picks the \n up as indicative of the end of a line of input, so it is effectively "skipped".

Either change the cin >> to a getline() or call cin.ignore() to grab the '\n'(or better, call a cin.ignore (std::numeric_limits<std::streamsize>::max(), '\n' ); to flush the input buffer-- but be sure you're not throwing away valuable input in the process).

Answer 2

It is because when you use getline() it ignores the newline at the end of the line and feeds it into the input queue, so when your getline function is called for next time it encounters the newline character discarded by the previous getline() and so it considers that as end of your input string. So thats why it doesn't take any input from you. You could use something like this

getline(cin,title);
cin.get();

hope this works.

Answer 3

I'd bet that you have something like a menu for selecting options ( as a numeric type ) and after that you try to read the lines.

This happens because after std::cin read some value the remaining '\n' was not processed yet, the solution would be to include #include <limits> and then put std::cin.ignore(std::numeric_limits<streamsize>::max(),'\n'); before your getline(cin,title);