MySQL query not working while using php variable in where clause

Question

I\'m new to PHP and MySQL. I am trying to make a simple search form using which I would want to show the results from the database based on the input text entered in the form. M

Answer 1

This should work:

$query = "SELECT * FROM cats WHERE name = '$name'";

Also, when you call "exit;" in the following block it will cancel the execution of the rest of your script:

    if (!empty($results)){
     echo "query successful" ;
     exit;
    }

Answer 2

You're escaping the $ in the variable by doing \$. Try:

$query = "SELECT * FROM `cats` WHERE name='$name'";

EDIT

From the discussion below.

The problem with the undefined index is the fact that you are using $row['age'] when really, the column name in the database is Age. Therefore you must use $row['Age'] when referring to the item. The same goes for name.

Answer 3

$query = "SELECT * FROM `cats` WHERE name='" . $name . "'";

or without concatenation

$query = "SELECT * FROM `cats` WHERE name='$name'";