Check if a word exists in a dictionary doesn't find any word

Question

I want to find the dictionary contain that word or not. Word comes from the list is incrementing by a loop. Please give a suggestion if you\'re not getting question comment belo

Answer 1

You pinpointed the problem:

if list[i] in d == True:

list[i] in d == True chains operators in and == in short-circuit fashion (like (list[i] in d) and (d==True))

Since d is different from True, global condition is always False and it seems that the word is not in the dictionary whereas it is.

Either protect with parentheses (works, but ugly):

if (list[i] in d) == True:

or use pythonic truth test (never compare to True or False anyway, use in d or not in d):

if list[i] in d:

BTW as COLDSPEED noted, now that the statement works, you'll have an error here because d has no integer keys:

print(d[i])   # d[list[i]] would be correct (but ugly)

So rewrite your loop getting rid of the indexes while you're at it,directly iterating on the elements (and getting rid of list as a variable as this is the list type, switched to l):

for item in l:
    if item in d:
        print(item)

nicer right?