Having the following table (conversations):
id | record_id | is_response | text |
---+------------+---------------+------------
Here's my take:
SELECT
record_id,
string_agg(text, ' ' ORDER BY id) AS context
FROM (
SELECT
*,
coalesce(sum(incl::integer) OVER (ORDER BY id ROWS BETWEEN UNBOUNDED PRECEDING AND 1 PRECEDING),0) AS grp
FROM (
SELECT *, is_response AND text IN (SELECT text FROM responses) as incl
FROM conversations
) c
) c1
GROUP BY record_id, grp
HAVING bool_or(incl)
ORDER BY max(id);
This will scan the table conversations once, but I am not sure if it will perform better than your solution. The basic idea is to use a window function to count how maybe preceding rows within the same record, end the conversation. Then we can group by with that number and the record_id and discard incomplete conversations.
There is a simple and fast solution:
SELECT record_id, string_agg(text, ' ') As context
FROM (
SELECT c.*, count(r.text) OVER (PARTITION BY c.record_id ORDER BY c.id DESC) AS grp
FROM conversations c
LEFT JOIN responses r ON r.text = c.text AND c.is_response
ORDER BY record_id, id
) sub
WHERE grp > 0 -- ignore conversation part that does not end with a response
GROUP BY record_id, grp
ORDER BY record_id, grp;
count() only counts non-null values. r.text is NULL if the LEFT JOIN to responses comes up empty:
The value in grp (short for "group") is only increased when a new output row is triggered. All rows belonging to the same output row end up with the same grp number. It's then easy to aggregate in the outer SELECT.
The special trick is to count conversation ends in reverse order. Everything after the last end (coming first when starting from the end) gets grp = 0 and is removed in the outer SELECT.
Similar cases with more explanation: