Count most frequent word in row by R [duplicate]

Answer 1

If we need the "Count" and "Names" corresponding to the max "Count", we loop through the rows of the dataset (using apply with MARGIN = 1), use table to get the frequency, extract the maximum value from it and the names corresponding to the maximum value, rbind it and cbind with the original dataset.

cbind(df1, do.call(rbind, apply(df1[-1], 1, function(x) {
              x1 <- table(x)
             data.frame(Count = max(x1), Names=names(x1)[which.max(x1)])})))

#    Name    Mon    Tue    Wed    Thu    Fri    Sat    Sun Count  Names
#1   John  Apple Orange  Apple Banana  Apple  Apple Orange     4  Apple
#2  Ricky Banana  Apple Banana Banana Banana Banana  Apple     5 Banana
#3   Alex  Apple Orange Orange  Apple  Apple Orange Orange     4 Orange
#4 Robbin  Apple  Apple  Apple  Apple  Apple Banana Banana     5  Apple
#5  Sunny Banana Banana  Apple  Apple  Apple Banana Banana     4 Banana

---

Or we can use data.table

library(data.table)
setDT(df1)[, c("Names", "Count") := {tbl <- table(unlist(.SD))
                    .(names(tbl)[which.max(tbl)], max(tbl))}, by = Name]

Answer 2

Another approach would be to loop over all unique fruits as follows

fruits_unique <- unique(unlist(dat[-1]))
occurence <- sapply(fruits_unique, function(x) rowSums(dat[,-1] == x)) 
# Using this data to create the resulting columns
ind <- apply(occurence,1,which.max)
dat$Names <- fruits_unique[ind]
dat$count <- occurence[cbind(seq_along(ind), ind)]

Result:

    Name    Mon    Tue    Wed    Thu    Fri    Sat    Sun  Names Count
1   John  Apple Orange  Apple Banana  Apple  Apple Orange  Apple     4
2  Ricky Banana  Apple Banana Banana Banana Banana  Apple Banana     5
3   Alex  Apple Orange Orange  Apple  Apple Orange Orange Orange     4
4 Robbin  Apple  Apple  Apple  Apple  Apple Banana Banana  Apple     5
5  Sunny Banana Banana  Apple  Apple  Apple Banana Banana Banana     4